我有一个包含应用程序版本的文件夹，每次上载新版本时，都会为此文件夹创建一个新的子文件夹，该子文件夹的名称是当前时间戳，这是所用主文件夹的打印输出(ls- l | grep ^ d):
drwxrwxr-x 7 root root 4096 2011-03-31 16:18 20110331161649
drwxrwxr-x 7 root root 4096 2011-03-31 16:21 20110331161914
drwxrwxr-x 7 root root 4096 2011-03-31 16:53 20110331165035
drwxrwxr-x 7 root root 4096 2011-03-31 16:59 20110331165712
drwxrwxr-x 7 root root 4096 2011-04-03 20:18 20110403201607
drwxrwxr-x 7 root root 4096 2011-04-03 20:38 20110403203613
drwxrwxr-x 7 root root 4096 2011-04-04 14:39 20110405143725
drwxrwxr-x 7 root root 4096 2011-04-06 15:24 20110406151805
drwxrwxr-x 7 root root 4096 2011-04-06 15:36 20110406153157
drwxrwxr-x 7 root root 4096 2011-04-06 16:02 20110406155913
drwxrwxr-x 7 root root 4096 2011-04-10 21:10 20110410210928
drwxrwxr-x 7 root root 4096 2011-04-10 21:50 20110410214939
drwxrwxr-x 7 root root 4096 2011-04-10 22:15 20110410221414
drwxrwxr-x 7 root root 4096 2011-04-11 22:19 20110411221810
drwxrwxr-x 7 root root 4096 2011-05-01 21:30 20110501212953
drwxrwxr-x 7 root root 4096 2011-05-01 23:02 20110501230121
drwxrwxr-x 7 root root 4096 2011-05-03 21:57 20110503215252
drwxrwxr-x 7 root root 4096 2011-05-06 16:17 20110506161546
drwxrwxr-x 7 root root 4096 2011-05-11 10:00 20110511095709
drwxrwxr-x 7 root root 4096 2011-05-11 10:13 20110511100938
drwxrwxr-x 7 root root 4096 2011-05-12 14:34 20110512143143
drwxrwxr-x 7 root root 4096 2011-05-13 22:13 20110513220824
drwxrwxr-x 7 root root 4096 2011-05-14 22:26 20110514222548
drwxrwxr-x 7 root root 4096 2011-05-14 23:03 20110514230258
我正在寻找一个将保留最后10个版本(子文件夹)并删除其余版本的命令。
有什么想法吗？
最佳答案
妳去(已编辑)ls -dt */ | tail -n +11 | xargs rm -rf
首先列出最近修改过的目录，然后将除前10个目录外的所有目录都接收，然后将其发送到rm -rf。
关于Linux-仅保存最近的10个文件夹，然后删除其余文件夹，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/6024088/