我有一个sql,我在php中使用pg_query_params运行它。但是,如果我尝试用BEGIN;and COMMIT将其转换为事务,则会出现以下错误:Query failed: ERROR: cannot insert multiple commands into a prepared statement
是否可以在同一个查询中使用多个语句准备事务?或者我应该如何修改它来进行交易?
谢谢!
WITH usr1 AS (
SELECT id FROM users WHERE mongoid = $1
),
usr2 AS (
INSERT INTO users (mongoid, shopid, idinshop, attributes)
SELECT $1, $2, $3, $4
WHERE NOT EXISTS (SELECT 1 FROM usr1)
RETURNING id
),
ses1 AS (
UPDATE sessions
SET traffic=$7, counts=$8
WHERE mongoid=$5
RETURNING id
),
ses2 AS (
INSERT INTO sessions (mongoid, shopid, userid, session, traffic, counts)
SELECT $5, $2, (SELECT id FROM usr1 NATURAL FULL OUTER JOIN usr2),
$6, $7, $8
WHERE NOT EXISTS (SELECT 1 FROM ses1)
RETURNING id
)
INSERT INTO events (shopid, sessionid, userid, type, attributes, mongoid)
VALUES (
$2,
(SELECT id FROM usr1 NATURAL FULL OUTER JOIN usr2),
(SELECT id FROM ses1 NATURAL FULL OUTER JOIN ses2),
$9, $10, $11
);
然后我运行:
pg_query_params($db, $sql, array(...))
最佳答案
您不需要begin/commit
块。整个陈述本身就是一个交易
create table t (id int primary key);
with s as (
insert into t values (1)
returning id
)
insert into t (id)
select id from s
;
ERROR: duplicate key value violates unique constraint "t_pkey"
DETAIL: Key (id)=(1) already exists.
CTE(
with...
)插件已回滚:select * from t;
id
----
(0 rows)
http://sqlfiddle.com/#!12/0eeef/2
从manual开始:
PostgreSQL实际上将每个SQL语句都视为在事务中执行。如果不发出BEGIN命令,则每个语句都有一个隐式BEGIN和(如果成功)COMMIT包装。
关于php - 如何将sql转换为具有多个语句的事务?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/18822662/