我有两个数组
var arr1 = ['wq','qw','qq'];
var arr2 = ['wq','wq','wq','qw','qw','qw','qw','qq','qq'];
我做的下面是将
arr1
值与arr2
匹配。如果数组包含相同的值,则将这些值压入newArr
。var newArr = [];
for (var i=0;i<arr1.length;i++) {
newArr[i] = [];
}
for (var i=0;i<arr2.length;i++) {
for (var j=0;j<arr1.length;j++) {
if (arr2[i].indexOf(arr1[j]) != -1)
newArr[j].push(arr2[i]);
}
}
console.log(newArr[1]); //newArr[0] = ['wq','wq','wq'];//In second output array newArr[1] = ['qw','qw','qw','qw'];
有没有一种简单的方法可以解决此问题,而无需使用两个for循环。更好,我需要使用javascript解决方案
最佳答案
也许使用indexOf()
:
var count = 0;
for (var i = 0; i < arr1.length; i++) {
if (arr2.indexOf(arr1[i]) != -1) {
count++;
// if you just need a value to be present in both arrays to add it
// to the new array, then you can do it here
// arr1[i] will be in both arrays if you enter this if clause
}
}
if (count == arr1.length) {
// all array 1 values are present in array 2
} else {
// some or all values of array 1 are not present in array 2
}