java - Android/Java-将DataInputStream转换为String

我目前与某些中间件建立了连接，通过该连接我可以将SQL查询发送到数据库。

将DataInputStream转换为可用格式（无论是否为String）时遇到麻烦。我查看了another StackOverflow question，但是由于使用

in.readLine();

被“弃用”，这意味着什么。我需要能够读取中间件的响应。

private class NetworkTask extends AsyncTask<String, Void, Integer>
{
    protected Integer doInBackground(String... params)
    {
        Message message = networkHandler.obtainMessage();

        String ip = "example ip";
        int port = 1234;

        try
        {
            InetAddress serverAddr = InetAddress.getByName(ip);
            Log.d("EventBooker", "C: Connecting...");
            Socket socket = new Socket(serverAddr, port);

            DataInputStream in = new DataInputStream(socket.getInputStream());


            try
            {
                Log.d("EventBooker", "C: Connected. Sending command.");
                PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(socket.getOutputStream())), true);
                out.println(params[0]);
                networkHandler.sendMessage(message);
                Log.d("EventBooker", "C: Sent.");
            }
            catch (Exception e)
            {
                Log.e("EventBooker", "S: Error", e);
            }
            Log.d("EventBooker", "C: Reading...");



            Log.d("EventBooker", "C: Response read, closing.");
            socket.close();
            Log.d("Eventbooker", "C: Closed.");
        }
        catch (Exception e)
        {
            Log.e("EventBooker", "C: Error", e);
        }
        return 1;
    }
}

最佳答案

像这样将DataInputStream转换为BufferedReaderStream：

BufferedReader d = new BufferedReader(new InputStreamReader(in));

然后，您想要获取实际的String，要执行以下操作：

StringBuffer sb = new StringBuffer();
String s = "";

while((s = d.readLine()) != null) {
    sb.append(s);
}

String data = sb.toString();

//Use data for w/e

简单容易！

我们之所以不将其附加到已经存在的字符串上，是因为Java Strings是不可变的，因此每次重新创建String对象时，都会造成性能问题。因此，StringBuffer！