我需要知道如何使用Java检测以太网电缆是否已插入或拔出,我使用NetworkInterface
来检查接口,但是当电缆拔出并再次插入时,我需要发出警报。
ArrayList<NetworkInterface> interfaces = Collections.list(NetworkInterface.getNetworkInterfaces());
for (NetworkInterface info : interfaces){
if(info.isUp()){
System.out.println(info.getName());
}
}
最佳答案
这是旧线程,但可能对研究人员有用。
根据J R的响应进行了修改。
import javafx.beans.property.BooleanProperty;
import javafx.beans.property.SimpleBooleanProperty;
import java.net.NetworkInterface;
import java.net.SocketException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Enumeration;
public class EthernetCableDetector implements Runnable{
private NetworkInterface iNet;
private boolean isRunning = true;
private BooleanProperty pluged = new SimpleBooleanProperty(false);
public boolean isPluged() {
return pluged.get();
}
public BooleanProperty plugedProperty() {
return pluged;
}
public void setPluged(boolean pluged) {
this.pluged.set(pluged);
}
public EthernetCableDetector(String localAddress) {
/**
* Acquire the list of interfaces available in your OS.
*/
Enumeration<NetworkInterface> tempNetInterface = null;
try {
tempNetInterface = NetworkInterface.getNetworkInterfaces();
} catch (SocketException ex) {
ex.printStackTrace();
}
ArrayList<NetworkInterface> interfaces = new ArrayList<>(Collections.list(tempNetInterface));
/**
*Make another list containing only the real interfaces.
* Remember that depending on the machine and OS the condition if (iNet.getHardwareAddress() != null)
* may not be enought to find out if this interface is real or not, the method isVirtual() won't give
* you the truth but there are many other solutions for this problem.
*/
ArrayList<NetworkInterface> realInterfaces = new ArrayList<>(Collections.list(tempNetInterface));
for (NetworkInterface iNet : interfaces) {
try {
if (iNet.getHardwareAddress() != null) { //This verification might not be enought to find if a Interface is real.
realInterfaces.add(iNet);
}
/** From the real interface you should identify which ones are ethernet connections.
* (if they are wireless there will be no cables involved). For windows you can verify
* if the method getName() returns something like "eth0" or "eth1", if yes it is a ethernet connection.
*/
if (iNet.getName().contains("eth") && iNet.getInetAddresses().hasMoreElements() && iNet.getInetAddresses().nextElement().getHostAddress().equals(localAddress)) {
System.out.println(localAddress + " Found.");
this.iNet = iNet;
/*
boolean previousStatus = iNet.isUp();
if (iNet.isUp() != previousStatus) {
// Interface cable must habe been plugged or unplugged.
previousStatus = iNet.isUp();
System.out.println("Cable status has changed " + iNet.isUp());
}
*/
}
} catch (SocketException ex) {
//TODO handle exception
}
}
}
@Override
public void run() {
Globals.pause(5000);
boolean previousStatus = false;
try {
previousStatus = iNet.isUp();
setPluged(previousStatus);
} catch (SocketException e) {
e.printStackTrace();
}
System.out.println("Cable status = " + previousStatus);
while(isRunning)
{
Globals.pause(250);
try {
setPluged(iNet.isUp());
if (iNet.isUp() != previousStatus) {
// Interface cable must habe been plugged or unplugged.
previousStatus = iNet.isUp();
System.out.println("Cable status =" + iNet.isUp());
}
} catch (SocketException e) {
e.printStackTrace();
}
}
}
public void stop(){
isRunning = false;
}
public static void main(String[] args) {
new EthernetCableDetector("192.168.10.26").run();
}
}