python - 查找并显示带有近似关闭条目的行

我正在编写代码，以查找不是重复的内容，而是在csv文件中近似关闭的值。
我希望能够找到同一行中所有差异不超过1.0的值
csv文件如下所示：

Time    Chan1   Chan2
04:07.0 52.31515503 16.49450684
04:07.1 23.55230713 62.48802185
04:08.0 46.06217957 24.94955444
04:08.0 41.72077942 31.32516479
04:08.0 19.80723572 25.73182678

我想找到Chan1.0和Chan 2彼此之间的值不超过1.0。
这就是我所拥有的：

import nump as np
from matplotlib import *
from pylab import *
filename = raw_input("Enter file name: ")+'.csv'
filepath = 'home/home/david/Desktop/'+filename
col1=[row[2] for row in data]
col2=[row[3] for row in data]

但是我不知道从这里去哪里，我不知道是否应该使用“ if”状态，或者是否有其他方法来获取所需的信息。我最终希望该程序打印3件事：

在Chan1和Chan2中找到非常接近（接近
这是我刚进行的修改：

import numpy as np
from matplotlib import *
from pylab import *


filename = raw_input("Enter file name: ") + '.csv'
filepath = '/home/david/Desktop/' + filename


data = np.genfromtxt(filepath, delimiter=',', dtype=float)




first=[row[0] for row in data]
rownum1=[row[1] for row in data]
rownum2=[row[2] for row in data]

#if (abs(rownum1-rownum2)<=1):
#       print( first, rownum1, rownum2)

count=0
for row in data:
     count++
     if (abs(row[1]-row[2]) <= 1.0):
            print('The values in row 0 are 1 and 2, are within 1.0 of each other.', format(count, row[1], row[2])

最佳答案

我认为我们可以使用标准库功能解决您的问题。

请注意：

这三行

first=[row[0] for row in data]
rownum1=[row[1] for row in data]
rownum2=[row[2] for row in data]

将执行3 x 10.000循环，最好在读取每行数据时进行拆分。

并请按照@ 0O0O0O0请求复制粘贴错误

try:
    text_file = open("list_number.txt", "r") #File contain your 5 line data, with header removed

    try:
        count = 0
        for row in text_file:
            col = row.split() # switch to row.split(',') if you're using coma delimiter
            count+=1
            if abs(float(col[1]) - float(col[2])) <= 10: # Change to 1
                #print('The values in row %s are %s and %s, are within 10.0 of each other.' % (count, col[1], col[2]))
                print('The values in row {0} are {1} and {2}, are within 10.0 of each other.'.format(count, col[1], col[2]))
    finally:
        text_file.close()

except IOError as e:
    print("Unable to open file : ", e)