我想有效地对JavaFX TableView进行“轮询”,以便如果另一个用户在数据库中创建了一个作业,则当前用户会选择该作业(比方说每5秒钟一次)。

我已经尝试过使用计时器;

new Timer().schedule(new TimerTask() {
    @Override
    public void run() {
        try {
            newI(connection, finalQuery, adminID);
        } catch (SQLException e) {
            e.printStackTrace();
        }
    }
}, 0, 5000);


但是,这会出现以下错误:我认为Exception in thread "Timer-0" java.lang.IllegalStateException: This operation is permitted on the event thread only; currentThread = Timer-0表示JavaFX不支持它?我如何能够定期更新JavaFX中的TableView?

最佳答案

您可以使用ScehduleService-这样的东西...

private class MyTimerService extends ScheduledService<Collection<MyDTO>> {
    @Override
    protected Task<Collection<MyDTO>> createTask() {
        return new Task<Collection<MyDTO>>() {
            @Override
            protected Collection<MyDTO> call() throws ClientProtocolException, IOException {
                   //Do your work here to build the collection (or what ever DTO).
                return yourCollection;
            }
        };
    }
}

    //Instead of time in your code above, set up your schedule and repeat period.
    service = new MyTimerService () ;
    //How long the repeat is
    service.setPeriod(Duration.seconds(5));
    //How long the initial wait is
    service.setDelay(Duration.seconds(5));

    service.setOnSucceeded(event -> Platform.runLater(() -> {
        //where items are the details in your table
        items =     service.getValue();
    }));

    //start the service
    service.start();

关于java - 定期刷新JavaFX TableView,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32481466/

10-14 11:17