╔═════════════╦════════════╗
║ posts ║ categories ║
╠═════════════╬════════════╣
║ id ║ id ║
║ title ║ name ║
║ slug ║ slug ║
║ content ║ ║
║ category_id ║ ║
╚═════════════╩════════════╝
给定类别的
slug
,我想从该类别中选择所有帖子。这些帖子与类别的category_id
-> id
链接。SELECT `posts.title`
FROM `categories`
INNER JOIN `posts`
ON `posts`.`division` = "1"
WHERE `category_slug` = "$category_slug"
它给了我一个
Unknown column 'posts.title' in 'field list'
。给定类别的标签,如何选择所有帖子? 最佳答案
看起来像你想要的
SELECT `posts`.`title`
代替
SELECT `posts.title`
关于mysql - 选择帖子内部联接类别,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/11770256/