例如,我有与子类别相关的产品:我有类似的类别Toys
,Toys -> ChildToys
,Toys -> ChildToys -> Cars
我有与Toys -> ChildToys -> Cars
相关的产品,我可以通过Cars
获得所有产品,但是如何通过过滤Toys
类别来获得产品。到目前为止我做了什么
class Category(models.Model):
name = models.CharField(max_length=100)
slug = models.SlugField(max_length=100, blank=True, unique=True)
icon = models.ImageField(upload_to='category_icons', null=True, blank=True)
parent = models.ForeignKey('self', on_delete=models.SET_NULL, related_name='children', null=True, blank=True)
class Product(models.Model):
category = models.ForeignKey(Category, blank=True, null=True, on_delete=models.CASCADE)
name = models.CharField(max_length=200)
class ProductList(generics.ListAPIView):
serializer_class = ProductSerializer
def get_queryset(self):
slug = self.request.query_params.get('slug', None)
parent_id = Category.objects.get(slug=slug)
cats = Category.objects.filter(parent_id=parent_id)
qs = Product.objects.filter(category_id__in=parent_id)
print(qs)
return qs
最佳答案
如果需要下降整个子树,则需要在Category
模型上创建一个递归获取所有子类别的方法。 another post向您显示如何执行此操作。
因此,假设您具有该方法Category.get_family_tree()
class Category(models.Model):
# fields
def get_family_tree(self):
# code from question linked above
# returns list of `Category` instances
然后您认为可以提取以下产品:
def get_queryset(self):
slug = self.request.query_params.get('slug')
categories = Category.objects.get(slug=slug).get_family_tree()
return Product.objects.filter(category__parent__in=categories)
关于python - 从父类别的django rest获得所有产品,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/59267201/