我是Golang的新手，正在尝试使用goroutines，以便它们之间可以进行交谈。我有一些代码启动一个具有operation1的goroutine，我称它为跳舞。完成后，它会向另一个goroutine发送信号，该goroutine将执行其他操作2，例如，睡眠。
您可以将强制舞蹈参数传递给舞蹈goroutine，但是如果它已经处于舞蹈状态，它将进入睡眠状态。
package main
import (
"fmt"
"time"
)
func main(){
test("notdancing", true)
time.Sleep(10*time.Second)
}
func dance()error{
fmt.Println("Tapping my feet")
time.Sleep(10*time.Second)
return nil
}
func test(status string, forceDance bool) {
这在以下情况下不起作用
//startSleep := make(chan bool)
为什么需要为通道提供缓冲区长度才能使其正常工作？我尝试了没有缓冲区长度的尝试，但是它说如果我不将1作为第二个参数传递，则所有goroutine都处于睡眠状态。
startdance := make(chan bool, 1)
startSleep := make(chan bool, 1)
if status == "dancing" && forceDance {
select {
case startSleep <-true:
fmt.Println("Would start to sleep now")
default:
fmt.Println("Sleep Already started. No need to force")
}
}
if status != "dancing" {
fmt.Println("Startingdance")
startdance <- true
}
go func() {
<-startdance
err := dance()
if err == nil {
select {
case startSleep <- true:
fmt.Println("Starting Sleeping, dancing completed")
default:
fmt.Println("Already started Sleeping")
}
} else {
fmt.Println("Not in a mood to dance today")
}
}()
go func() {
<-startSleep
if forceDance {
fmt.Println("Force sleep because forcing to dance while already dancing")
}
}()
}
我非常感谢对代码的任何更正以及使用此方法的陷阱。
最佳答案
如果是非缓冲通道(未指定大小)，则由于没有大小，因此无法保存值。因此，在通过通道写入/传输数据时，必须有读者在场，否则它将阻塞 call 。
func main() {
startDance := make(chan bool)
startDance <- true
}
但是，当您在上面的代码中指定大小(例如1)时，它不会死锁，因为它将有空间容纳数据。 ((https://robertbasic.com/blog/buffered-vs-unbuffered-channels-in-golang/)。)(https://www.golang-book.com/books/intro/10)您可以查看上述网站，以更好地了解渠道和并发性
package main
import (
"fmt"
"time"
)
func main() {
startDance := make(chan bool)
startSleep := make(chan bool)
forceSleep := make(chan bool)
go startDance1(startDance, forceSleep, startSleep)
go performSleep(startSleep, startDance)
startDance <- true
fmt.Println("now dance is started ")
forceSleep <- true
select {}
}
func startDance1(startDance chan bool, forceSleep chan bool, startSleep chan bool) {
fmt.Println("waiting to start dance")
select {
case <-startDance:
fmt.Println("staring dance")
}
for {
select {
case <-startDance:
fmt.Println("starting dance")
case <-forceSleep:
fmt.Println("aleardy dancing going to sleep")
select {
case startSleep <- true:
default:
}
default:
//this is just to show working this
// i added default or else this will go into deadlock
fmt.Println("dancing")
time.Sleep(time.Second * 1)
}
}
}
func performSleep(startSleep chan bool, startDance chan bool) {
select {
case <-startSleep:
fmt.Println("staring sleep")
}
fmt.Println("sleeping for 5 seconds ")
time.Sleep(time.Second * 5)
select {
case startDance <- true:
fmt.Println("started dance")
default:
fmt.Println("failed to start dance ")
}
}
上面的代码是对您的代码的一个小改进(我尝试根据您的要求进行修改)。我建议您阅读一些书籍，以进一步了解go并发(https://www.golang-book.com/books/intro/10_