如何解码没有字段名称的字符串和整数 slice ?
这是我尝试解码的远程API的输出:
[["9BC67ACD", "example1", "example1.co.uk", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "FINISHED", 1], ["B339CBA2", "example2", "example2.co.uk", "2018-08-06 08:38:25", "2018-08-06 08:38:24", "2018-08-06 08:38:27", "FINISHED", 1]]
做完后我得到了一个字节
rBody, err := ioutil.ReadAll(r.Body)
我可以使用带有
[][]interface{}
的json解码器对此进行解码吗? 最佳答案
您的问题:-
是的,您可以解码JSON输出没有问题。这是JSON数组。
[["9BC67ACD", "example1", "example1.co.uk", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "FINISHED", 1], ["B339CBA2", "example2", "example2.co.uk", "2018-08-06 08:38:25", "2018-08-06 08:38:24", "2018-08-06 08:38:27", "FINISHED", 1]]
或者,您可以将JSON解码到接口(interface){}中。但是在两种情况下,您都需要类型断言来获取接口(interface)的基础值。
package main
import (
"fmt"
"encoding/json"
)
var jsonBytes string = `[["9BC67ACD", "example1", "example1.co.uk", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "2018-08-06 08:46:44", "FINISHED", 1], ["B339CBA2", "example2", "example2.co.uk", "2018-08-06 08:38:25", "2018-08-06 08:38:24", "2018-08-06 08:38:27", "FINISHED", 1]]`
func main() {
var result interface{}
if err := json.Unmarshal([]byte(jsonBytes), &result); err != nil{
fmt.Println(err)
}
fetchValue(result) // This function recursively get the underlying value of an interface.
}
func fetchValue(value interface{}) {
switch value.(type) {
case string:
fmt.Printf("%v is an string \n ", value.(string))
case bool:
fmt.Printf("%v is bool \n ", value.(bool))
case float64:
fmt.Printf("%v is float64 \n ", value.(float64))
case []interface{}:
fmt.Printf("%v is a slice of interface \n ", value)
for _, v := range value.([]interface{}) {
fetchValue(v)
}
case map[string]interface{}:
fmt.Printf("%v is a map \n ", value)
for _, v := range value.(map[string]interface{}) {
fetchValue(v)
}
default:
fmt.Printf("%v is unknown \n ", value)
}
}
Playground example
关于json - 解码字符串和整数 slice ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/51704860/