python - Django:表单处理错误。处理与另一个模型关联的表单

我希望能够为老师提交评论。我有2个型号：

models.py

class Teacher(models.Model):
    user = models.OneToOneField(User, on_delete=models.PROTECT, related_name='Teacher')

class Review(models.Model):
    teacher = models.ForeignKey(Teacher)
    #other fields

    def __str__(self):
        return self.name

表格

class ReviewForm(forms.ModelForm):
    class Meta:
        model = Review
        #Note no 'teacher' in fields below
        fields = ('title','star','body')

views.py我有以下表单处理：

def teacher_view(request,**kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    #if request.method == 'POST':
    #handle the form
    review_form = ReviewForm(request.POST, instance=teacher)
    review_form.teacher=teacher
    if review_form.is_valid():
         review_form.save()
         return redirect('users:index')
    else:

由于某种原因，我似乎也得到了else循环。例如。表格无效。

Urls.py

url(r'^(?P<pk>[0-9]+)/$', views.teacher_view, name='detail')

完整Views.py

def teacher_profile(request, **kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    reviews = Review.objects.filter(teacher_id=kwargs['pk'])
    star = Review.objects.filter(teacher_id=kwargs['pk']).aggregate(Avg('star'))
    no_of_ratings = Review.objects.filter(teacher_id=kwargs['pk']).count()

    if request.method == "POST":
        if 'booking' in request.POST:
            form = BookingForm(request.POST)
            if form.is_valid():
                #handle the form
                return redirect('users:index')
            else:
                review_form = ReviewForm()
        elif 'review' in request.POST:
            review_form = ReviewForm(request.POST)
            review_form['teacher']=teacher
            if review_form.is_valid():
                review_form.save()
                return redirect('users:index')
            else:
                form = BookingForm()
        else:
            form = BookingForm()
            review_form = ReviewForm()
    else:
        form = BookingForm()
        review_form = ReviewForm()

    return render(request, "users/teacher_detail.html", context={"form": form,
                                                                 "review_form":review_form,
                                                                 "teacher":teacher,
                                                                 "reviews":reviews,
                                                                 "star":star,
                                                                 "no_of_ratings":no_of_ratings,
                                                                 })

我再次添加了代码。我已经从views.py复制粘贴了该文件，但是删除了我只定义变量并重定向到包含成功消息的另一页的表单处理。

我认为您的答案中的逻辑为什么错了，因为它首先检查表单是否有效，而这是因为缺少老师而无效。然后，在检查教师是否有效之后，再对其进行定义。我尝试通过在review_form['teacher']=teacher之前添加form.is_valid()来操纵代码，但始终会收到错误：


  “ ReviewForm”对象不支持项目分配

最佳答案

如果ReviewForm有效，您似乎想添加教师：

def teacher_profile(request,**kwargs):
    teacher = Teacher.objects.get(pk=kwargs['pk'])
    reviews = teacher.review_set.all()
    star = reviews.aggregate(Avg('star'))
    no_of_ratings = reviews.count()

    form = BookingForm()
    review_form = ReviewForm()

    if request.method == "POST":
        if 'booking' in request.POST:
            form = BookingForm(request.POST)
            if form.is_valid():
                #Correct handling
                return redirect('users:index')
        elif 'review' in request.POST:
            review_form = ReviewForm(request.POST)
            if review_form.is_valid():
                review = review_form.save(commit=False)
                review.teacher = teacher
                review.save()
                return redirect('users:index')
    context = {
       "form":form,
       "review_form":review_form,
       "teacher":teacher,
       "reviews":reviews,
       "star":star,
       "no_of_ratings":no_of_ratings,})
    return render(request, "users/teacher_detail.html", context)

在teacher_detail.html添加中，

{{ review_form.errors }}