我在Spring中有一个基于令牌的身份验证方案。但是JWTParser似乎很麻烦。以下代码中的JWTParser类实际上做什么?另外,我无法导入此类。
public class JWTAuthenticationToken extends AbstractAuthenticationToken {
private static final long serialVersionUID = 1L;
private final Object principal;
private Object details;
Collection authorities;
public JWTAuthenticationToken( String jwtToken ) {
super( null );
super.setAuthenticated( true ); // must use super, as we override
JWTParser parser = new JWTParser( jwtToken );
this.principal = parser.getSub();
this.setDetailsAuthorities();
}
@Override
public Object getCredentials() {
return "";
}
@Override
public Object getPrincipal() {
return principal;
}
private void setDetailsAuthorities() {
String username = principal.toString();
SpringUserDetailsAdapter adapter = new SpringUserDetailsAdapter( username );
details = adapter;
authorities = ( Collection ) adapter.getAuthorities();
}
@Override
public Collection getAuthorities() {
return authorities;
}
}
有没有解决的办法?
最佳答案
JwtParser parser =new DefaultJwtParser();
parser.parse(jwtToken);
<dependency>
<groupId>io.jsonwebtoken</groupId>
<artifactId>jjwt</artifactId>
<version>0.6.0</version>
</dependency>