javascript - RegEx提取括号和函数名称

有人帮我写以下情况的RegEx

somestring()=> ['somestring']

somestring()[10] => ['somestring','',10]

somestring('argString')=> ['somestring', 'argString']

somestring('argString')[10] => ['somestring', 'argString',10]

somestring({prop1:'v1'，prop2:'v2'})=> ['somestring', {prop1:'v1',prop2:'v2'}]

somestring({prop1:'v1'，prop2:'v2'})[100] => ['somestring', {prop1:'v1',prop2:'v2'},100]

这是我到目前为止尝试过的

var regExp = /\b[^()]+\((.*)\)+\[(.*?)]/;
var matches = regExp.exec('somestring()[10]');

最佳答案

那可以工作:

var input = ['somestring()', 'somestring()[10]', "somestring('argString')", "somestring('argString')[10]", "somestring({prop1:'v1',prop2:'v2'})", "somestring({prop1:'v1',prop2:'v2'})[100]"];

console.log(input.map(function(v) {
  let result = v.match(/(.*)\((.*)\)(\[([^\]]*)\])?/);

  return [result[1], result[2], result[4]];
}));

关于javascript - RegEx提取括号和函数名称，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/41776900/