我有以下要概括的JAXB解组代码。看起来是这样的:
private Object getResponseObject(String stubbedXmlFile,
Class jaxbInterfaceClass,
AbstractRepository repository) {
Object responseObject = null;
try {
JAXBContext jc = JAXBContext.newInstance(jaxbInterfaceClass);
Unmarshaller u = jc.createUnmarshaller();
InputStream resourceAsStream = TestProvidePensionValuationRepository.class.getClassLoader()
.getResourceAsStream(stubbedXmlFile);
BufferedReader br = new BufferedReader(new InputStreamReader(resourceAsStream));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line);
}
br.close();
ByteArrayInputStream byteStream =
new ByteArrayInputStream(sb.toString().getBytes());
responseObject = u.unmarshal(byteStream);
} catch (JAXBException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return responseObject;
}
我的目标不是返回Object,而是返回作为参数传入的同一类(例如
jaxbInterfaceClass
)。我在想使用泛型可能会实现这一点,但作为通用的相对新手,我感到很困惑。任何帮助表示赞赏! 最佳答案
这根本不是一个JAXB问题,只是对所需的泛型进行了一些调整:
private <T> T getResponseObject(String stubbedXmlFile,
Class<T> jaxbInterfaceClass,
AbstractRepository repository) {
T responseObject = null;
// code as before
responseObject = (T) u.unmarshal(byteStream);
return responseObject;
}
这可能会引发编译器警告,但这在将泛型代码与非泛型代码(例如JAXB)桥接的代码中并不少见。
然后,您可以使用以下命令进行调用:
MyType x = getResponseObject(file, MyType.class, repo);
关于java - 泛型可以避免我回传一个泛型的“对象”吗?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/3924719/