我刚刚开始使用Java开设大学课程,并且在Scanner类中始终遇到此错误。

import java.util.Scanner;

public class InchConversion
{
    public static void main (String[] args)
    {
        Double inches, centimeters;
        Scanner fromKeyboard = new Scanner(System.in);
        System.out.println("Enter Value in Inches");
        inches = fromKeyboard.nextDouble();
        centimeters = inches*2.54;
        System.out. println(inches + " inches is equal to " + centimeters + " centimeters.");
    }
}


我不断得到的错误是:

  Compiling InchConversion.java.......
-----------OUTPUT-----------
Enter Value in Inches
Exception in thread "main" java.util.NoSuchElementException
    at java.util.Scanner.throwFor(Scanner.java:862)
    at java.util.Scanner.next(Scanner.java:1485)
    at java.util.Scanner.nextDouble(Scanner.java:2413)
    at InchConversion.main(InchConversion.java:11)
[Finished in 0.8s with exit code 1]

最佳答案

例如,您需要使用3.0作为输入,因为您明确告诉扫描程序期望float值,并且在Java中float需要十进制,即使它是整数。
Workouround将是:

double inches = Double.parseDouble(fromKeyboard.nextLine());


这样,您告诉扫描程序解析当前行上的第一个String值,该值也可以解释为double(在这种情况下,即使数字没有小数,java编译器也不在乎,它在解析过程中将其添加)。因此,如果输入20,它将自动全部加上小数和inches = 20.0。但是,如果要inches = 20.1,则仍必须输入20dot1。但是至少它摆脱了不直观和陌生的20.0输入。

编辑:我尝试用您的修复程序的代码,它对我来说很好

public static void main (String[] args) {
    Double inches, centimeters;
    Scanner fromKeyboard = new Scanner(System.in);
    System.out.println("Enter Value in Inches");
    inches = Double.parseDouble(fromKeyboard.nextLine());
    centimeters = inches*2.54;
    System.out.println(inches + " inches is equal to " + centimeters + " centimeters.");
}


如果输入1,则输出为1.0 inches is equal to 2.54 centimeters.

10-06 07:12
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