根据valgrind的说法,这个基本上是初始化结构的函数是泄漏源:
Item* InitializeItem(char* name, int reg, char* adress)
{
Item* i = (Item*)malloc(sizeof(Item));
int a = strlen(name) + 1;
int b = strlen(adress) + 1;
i->name = (char*)malloc(a*sizeof(char));
strcpy(i->name, name);
i->reg = reg;
i->adress = (char*)malloc(b*sizeof(char));
strcpy(i->adress, adress);
return i;
}
以下是免费功能:
List* Free_List(List* list)
{
Node* new;
new = list->First;
while (new != NULL)
{
Node* aux = new->prox;
free(new->item->name);
free(new->item->adress);
free(new->item);
free(new);
new = aux;
}
free(list);
}
我什么都试过了,但我不明白发生了什么很明显我解放了一切。
以下是我在运行valgrind时收到的两个泄漏错误--泄漏检查=完全:
41 (24 direct, 17 indirect) bytes in 1 blocks are definitely lost in loss record 5 of 6
43 (24 direct, 19 indirect) bytes in 1 blocks are definitely lost in loss record 6 of 6
以下是项目结构:
typedef struct item Item;
struct item
{
char *name;
int reg;
char *adress;
};
下面是列表和节点结构:
typedef struct list List;
struct list
{
Node* node;
Node *First, *Last;
};
typedef struct node Node;]
struct node
{
Item* item;
Node* prox;
};
在这里,初始化,插入和删除函数我想他们可能和这个错误有关:
List*
InitializeList()
{
List* list = (List*)malloc(sizeof(List));
list->First = list->Last = NULL;
return list;
}
void
Insert(Item* student, List* list)
{
Node* new = (Node*)malloc(sizeof(Node));
new->prox = NULL;
if (list->Last == NULL)
list->First = list->Last = new;
else
{
list->Last->prox = new;
list->Last = list->Last->prox;
}
new->item = student;
}
Item*
Remove(List* list, int reg)
{
Item* i = NULL;
Node* ant = NULL;
Node* seg = list->First;
while (seg != NULL && seg->item->reg != reg)
{
ant = seg;
seg = seg->prox;
}
if (seg == NULL)
{
i = NULL;
return i;
}
if (seg == list->First && seg == list->Last)
{
i = seg->item;
list->First = list->Last = NULL;
free(seg);
return i;
}
if (seg == list->Last)
{
i = seg->item;
list->Last = ant;
ant->prox = NULL;
free(seg);
return i;
}
if (seg == list->First)
{
i = seg->item;
list->First = seg->prox;
free(seg);
return i;
}
else
{
i = seg->item;
ant->prox = seg->prox;
free(seg);
return i;
}
free(seg);
}
这些是主函数的最后一行第一次调用Remove函数时:
Item* ret = Remove(list, 123);
ret = Remove(list, 34);
list = Free_List(list);
最佳答案
在insert
方法的这一行中:
list->Last = list->Last->prox;
您将失去对list->Last中先前内容的跟踪;将其值替换为新分配的指针;这样以前位于最后位置的项将永远不会被释放-->内存泄漏。
关于c - 我释放了一切,但内存正在泄漏,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32834913/