我有一个清单
str(overlaps)
List of 7
$ a5: chr [1:6] "calc_a1c" "predmdx_flag" "bmi" "systolic" ...
$ a2: chr [1:2] "age" "yr"
$ a4: chr(0)
$ a6: chr(0)
$ a1: chr [1:2] "trig_3cat" "glipizide_flag"
$ a3: chr [1:2] "email_flag" "statins_flag"
$ a7: chr [1:4] "trig_3cat.>=200" "antihtn_flag" "black_flag" "gender.M"
我想对列表重新排序，以使结果列表是其中元素按数字顺序排列的列表。即a1，a2，a3等
最佳答案
一些随机数据：
set.seed(42)
overlaps <- replicate(5, runif(3), simplify=FALSE)
names(overlaps) <- paste0("a", sample(5))
str(overlaps)
# List of 5
# $ a5: num [1:3] 0.915 0.937 0.286
# $ a4: num [1:3] 0.83 0.642 0.519
# $ a1: num [1:3] 0.737 0.135 0.657
# $ a3: num [1:3] 0.705 0.458 0.719
# $ a2: num [1:3] 0.935 0.255 0.462
排序：
str(overlaps[ sort(names(overlaps)) ])
# List of 5
# $ a1: num [1:3] 0.737 0.135 0.657
# $ a2: num [1:3] 0.935 0.255 0.462
# $ a3: num [1:3] 0.705 0.458 0.719
# $ a4: num [1:3] 0.83 0.642 0.519
# $ a5: num [1:3] 0.915 0.937 0.286
关于r - 列表元素的排序，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/37979757/