我正在寻找一种缩短此python3函数的方法。该函数需要很多输入变量,并检查每个变量是否为None。有没有一种方法可以遍历所有输入变量,并将不是None的变量添加到params字典中?
def news(self, query = None, instrument_id = None, days = None, news_lang = None, news_country = None, market_id = None, limit = None, offset = None, source_id = None):
params = {}
if query is not None:
params['query'] = query
if instrument_id is not None:
params['instrument_id'] = instrument_id
if news_lang is not None:
params['news_lang'] = news_lang
if news_country is not None:
params['news_country'] = news_country
if limit is not None:
params['limit'] = limit
if offset is not None:
params['offset'] = offset
if source_id is not None:
params['source_id'] = source_id
self.make_cmd('GET', 'news', params)
最佳答案
似乎所有参数都直接传递给make_cmd
,所以为什么不使用关键字参数:
def news(self, **params):
self.make_cmd('GET', 'news', params)
news(query="Test")
关于python - 如何使此代码段更漂亮?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/51338770/