我希望能够删除列表中不需要的一些单词。
码:
contour = cnt
stopwords = ['array', 'dtype=int32']
for word in list(contour):
if word in stopwords:
contour.remove(word)
print(contour)
输出:
[array([[[21, 21]],
[[21, 90]],
[[90, 90]],
[[90, 21]]], dtype=int32)]
FutureWarning: elementwise comparison failed; returning scalar instead, but in the future will perform elementwise comparison if word in stopwords:
如何删除
dtype=int32
和array
,同时使列表仅是两点的列表?例如:
[[21, 21],
[21, 90],
[90, 90],
[90, 21]]
最佳答案
使用numpy.ndarray.tolist()
:
import numpy as np
l = np.array(
[np.array([[[21, 21]],
[[21, 90]],
[[90, 90]],
[[90, 21]]], dtype="int32")]
)
l.tolist()
输出:
[[[[21, 21]], [[21, 90]], [[90, 90]], [[90, 21]]]]
关于python - 从嵌套列表中删除不需要的文本,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/56856861/