我有两个表：
table1:
id
--
1
2
3
table2: (left out primary index)
id2 | cond
----------
3 | 1
3 | 0
2 | 1
2 | 1
2 | 0
我需要构造一个隐式计算此中间表的查询：
temp:
id | c1 | c2
------------
1 | 0 | 2
2 | 2 | 2
3 | 1 | 2
使用
c1 = countRows(id2 == id && cone == 1)和c2 == countRows(id2 = 2 && cond == 1)。然后选择
SELECT id FROM temp ORDER BY ABS(c1 - c2)*RAND()。我目前的尝试有点像：
SELECT id, COUNT(t1.id2) AS c1, COUNT(t2.id2) AS c2
FROM table1 LEFT JOIN (table2 AS t1) ON id=t1.id2 LEFT JOIN (table2 AS t2) ON t2.id2=2
WHERE t1.cond=1 AND t2.cond=1
GROUP BY t1.id2
ORDER BY ABS(c1 - c2)*RAND()
LIMIT 1
其中有多个问题：
它不会选择table2中没有条目的行
它没有正确计数
ORDER BY第3部分中的组列（c1，c2）似乎存在问题。
帮助将不胜感激。
更新：
table1代表玩家
table2将进行回合，cond表示获胜
c1代表每个玩家赢得的回合
c2代表参考玩家（本例中为玩家2）赢得的回合
最佳答案
SELECT t1.id, SUM(IFNULL(t2.cond, 0) = 1) AS c1, (SELECT SUM(cond = 1) FROM table2 WHERE id2 = 2) AS c2
FROM table1 t1
LEFT JOIN table2 t2 ON t1.id = t2.id2
GROUP BY t1.id
ORDER BY ABS(SUM(IFNULL(t2.cond, 0) = 1) - c2) * RAND();