我有一个json文件，其中包含以下格式的数据。我正在为德鲁伊写索引任务来收集数据。它因时间戳（事件时间）而拒绝。
是否有方法将事件时间值从2016-11-30 23:59:53.654000转换为2016-11-30t23:59:53.654z？
JSON文件：{"app":14232,"device_carrier":"airtel","$schema":10,"city":"Bellary","user_id":"234293","uuid":"1d5b5328-b729-11e2-a0e5-22340a56812f","event_time":"2016-11-30 23:59:53.654000","platform":"Android","os_version":"4.4.2","insider_id":3426766963,"processed_time":"2016-12-01 00:00:05.429064","user_creation_time":"2015-12-14 18:34:04.632000","version_name":"2.08","ip_address":"117.266.132.112","paying":"true","dma":null,"user_properties":{"[SauceFlyer] campaign":"N\/A","[SauceFlyer] media source":"Chemical"},"client_upload_time":"2016-12-01 00:00:03.982000","$insert_id":"e43b2a4d-072f-2322-bd74-6bdb0b2e1f63","event_type":"Search","library":"insider-android\/2.9.2","device_type":"Micromax Owen Nitro","device_manufacturer":"Micromax","start_version":"1.57","location_lng":null,"server_upload_time":"2016-12-01 00:00:04.230000","event_id":286,"location_lat":null,"os_name":"android","insider_event_type":null,"device_brand":"Micromax","groups":{},"event_properties":{"Search Query":"clutches for women"},"data":{},"device_id":"ff71c4f0-81b8-4a44-8db1-1555e22f6761R","language":"English","device_model":"Micromax A310","country":"India","region":"Karnataka","adid":null,"session_id":1480550372776,"device_family":"Micromax Phone","idfa":null,"client_event_time":"2016-11-30 23:59:53.406000"}
最佳答案
如果您的输入位于input.json中，并且希望使用sed执行此操作：
sed 's/\([0-9]\{4\}-[0-9]\{2\}-[0-9]\{2\}\) \([0-9]\{2\}:[0-9]\{2\}:[0-9]\{2\}\.[0-9]\{3\}\)[0-9]\{3\}/\1T\2Z/g' input.json
（是的，我同意这很难看。）
但是，它会替换输入中的所有时间戳，假设这是您想要的。如果没有，则必须扩展regex以使其与之前的键匹配。
一个等效的perl一行程序“为了更好的可读性”：
cat input.json | perl -p -e 's/(\d{4}-\d{2}-\d{2}) (\d{2}:\d{2}:\d{2}.\d{3})\d{3}/\1T\2Z/g'