c++ - boost::msm-一种获取状态的字符串表示形式(即getName)的方法吗？

我正在尝试使用boost::msm库在我的代码中创建一个状态机。有谁知道一种获取状态的字符串名称(不是int id)的方法吗？我正在尝试将此用于日志记录/调试目的。例如在no_transition函数中，我获得了状态ID，但是我试图获得一个名称，因此更易于阅读:

template <class Event ,class Fsm>
    void no_transition(Event const& e, Fsm& fsm, int stateId)
    {
        //This is what I'm trying:
        auto state = fsm.get_state_by_id(stateId); //This returns a boost::msm::front::default_base_state. Anything I can override in there to set a name?
        const char* stateName = state->getStateName(); //I want to do something like this since I can do e.getEventId()

        print("FSM rejected the event %s as there is no transition from current state %s (%d)\n", e.getEventId(), stateName, stateId);
    }

这是我定义事件和状态的方式:
状态:

struct Idle : front::state<> {
 static const char* const getStateName() {
        return "Idle";
    }
};

事件:

struct SampleEvent {
    SampleEvent() {}
    static const char* const getEventId() {
        return "SampleEvent";
    }
};

任何想法都很棒。谢谢!

最佳答案

您可以使用以下代码获得所需的效果:

 #include <boost/msm/back/tools.hpp>
 #include <boost/msm/back/metafunctions.hpp>
 #include <boost/mpl/for_each.hpp>
  .......
  .......
    template <class Event ,class Fsm>
    void no_transition(Event const& e, Fsm& fsm, int stateId){
        typedef typename boost::msm::back::recursive_get_transition_table<FSM>::type recursive_stt;
        typedef typename boost::msm::back::generate_state_set<recursive_stt>::type all_states;
        std::string stateName;
        boost::mpl::for_each<all_states,boost::msm::wrap<boost::mpl::placeholders::_1> >(boost::msm::back::get_state_name<recursive_stt>(stateName, state));
        std::cout << "No transition from state: " << stateName << std::endl;}