我正在为使用自定义UITableViewCell子类的UITableView进行自定义滑动事件。我在标头中包含了UIGestureRecognizerDelegate,并将其包含在viewDidLoad:

UISwipeGestureRecognizer *swipeLeft = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(didSwipe:)];
swipeLeft.direction = UISwipeGestureRecognizerDirectionLeft;
swipeLeft.numberOfTouchesRequired = 1;
[self.tableView addGestureRecognizer:swipeLeft];

我的swipeLeft方法如下所示:
-(void)didSwipe:(UISwipeGestureRecognizer *)recognizer {

    if (recognizer.state == UIGestureRecognizerStateEnded)
    {
        CGPoint swipeLocation = [recognizer locationInView:self.tableView];
        NSIndexPath *swipedIndexPath = [self.tableView indexPathForRowAtPoint:swipeLocation];
        NSDictionary *clip = [self.clips objectAtIndex:swipedIndexPath.row];
        NSLog(@"Swiped!");


    }
}

有点工作,但是滑动必须非常精确。几乎不可能精确。

我几乎是通过使用UIPanGestureRecognizer使它工作的,但不幸的是,它与使用全局平移手势识别器(ECSlidingViewController的用户)的全局边抽屉组件配合使用效果不佳。

有没有办法解决?任何帮助将不胜感激,因为我一直在谷歌搜索和浏览SO数小时以寻找解决方案。

最佳答案

正如Kolin Krewinkel在Twitter上所指出的那样,实现这2个委托方法可以解决问题:

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer
{
    return YES;
}

- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
    return YES;
}

关于ios - UITableView滑动手势需要近乎完美的准确性,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/15890305/

10-12 03:13
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