php - MySQL的:完全匹配？

我正在从mysql中提取一些数据并计算匹配项的出现（看似等同于WHERE foo='bar'）。但是，当我遍历PHP中的数据时，我的计数比mysql中的计数低得多。

MYSQL> SELECT COUNT(foo) FROM database.table WHERE foo='bar';

# PHP
while ($response = mysql_fetch_assoc($surveydata)){
    if ($response==='bar') {
        $bar++;
    }
}

数据可能包含一个或多个&，因此我只想匹配bar，而不要匹配bar & foobar。我怀疑mysql正在计数bar和bar & foobar，而php仅计数bar而不是bar & foobar。 PHP返回1210，而mysql返回1783，因此手动计数以查看谁是正确的是完全可行的……

我四处搜寻，但感到惊讶的是，“ mysql完全匹配”或“ mysql完全相等”没有相关的信息x，x

编辑

这是实际的SQL

SELECT COUNT(`race`) FROM `database`.`table` WHERE `completion status`='complete';

和实际的PHP

mysql_query("SELECT `race`,`etcetera` FROM `database`.`table` WHERE `completion status`='complete';");

$demographics=array(
    "race"=>array(
        "White"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Black"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Hispanic"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Asian"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Pacific Islander"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Multiracial"=>array('consented'=>0,'partial'=>0,'completed'=>0),
        "Other"=>array('consented'=>0,'partial'=>0,'completed'=>0)
    )
    //more
);

while ($dbrecord = mysql_fetch_assoc($surveydata)) {
    foreach ( $dbrecord as $dbfield=>$dbcellval ) {
        foreach ( $demographics as $demographic=>&$options ) {
            foreach ( $options as $option=>&$counter ) {
                if ( $option==="Multiracial" && strpos($dbcellval,'&') >0 && strpos($dbcellval,'&')!==false ) {
                    if ($dbrecord['consent']==="1"){
                        $demographics["race"]["Multiracial"]['consented']++;
                        if ($dbrecord['completion status']==="partial") {
                            $demographics["race"]["Multiracial"]['partial']++;
                        } // if
                        else if ($dbrecord['completion status']==="complete") {
                            $demographics["race"]["Multiracial"]['completed']++;
                        } // else if
                    } // if
                }
                else if ($option===$dbcellval){
                    if ($dbrecord['consent']==="1"){
                        $counter['consented']++;
                        if ($dbrecord['completion status']==="partial") {
                            $counter['partial']++;
                        } // if
                        else if ($dbrecord['completion status']==="complete") {
                            $counter['completed']++;
                        } // else if
                    } // if
                } // else if $option==$item
            } // foreach $options
        } // foreach $demographics
    } // foreach $dbrecord
} // while

SELECT race FROM database.table中的数据如下所示：

White & Black
White
White & Asian
White & Asian & Black
Asian
Asian & Black
// etc

最佳答案

你可以这样做：

MYSQL> SELECT COUNT(foo) FROM database.table WHERE BINARY foo='bar';

BINARY做魔术！！！