javascript - 如何使用Javascript找到(很快-15-20ms)LatLong地址？

我有一个socket.io，它每15到20毫秒ping一个新地址。对于此地址，我必须获取经纬度并将标记放置在Google地图中。因此，在那15-20毫秒内（如果不是，可能在50-60毫秒内），我必须获取GeoLocation。目前，我正在使用geocoder = new google.maps.Geocoder();，然后使用geocoder.geocode({address: data}, myFunction(){});

但是此Maps API非常慢。它在400-500毫秒内返回GeoLocation，这使我的中间地址请求为空。我需要一个非常快的API。

作为参考，以下是socket.io的代码段：

geocoder = new google.maps.Geocoder();
    var socket = io.connect('http://localhost');
    socket.on('new_address', function (data) {
        //Gets called everytime a new request for GeoLocation comes
        geocoder.geocode({address: data}, placeMarker);
    });

var placeMarker = function(){
    //Add Marker to GoogleMaps
};

最佳答案

正如评论中提到的那样，您实际上不能期望互联网上20毫秒内有响应，但是那样行不通。但是，您要做的就是使用地址建立某种池，然后让地址解析器（或4之3）按照自己的速度对其进行处理。

这可能看起来像这样（只是在这里给出一个方向，不要指望它立即起作用）：

var addresses = [];
var socket = io.connect('http://localhost');
socket.on('new_address', function (data) {
    //Gets called everytime a new request for GeoLocation comes
    //Adds an address to the list when it comes in from the backend
    adresses.push(data);
});

var geocoder = new google.maps.Geocoder();
//This function is called in a loop.
var addressCheck = function() {
    //When the list of addresses is empty, because we haven't received anything from the backend, just wait for a bit and call this function again.
    if(addresses.length == 0) {
        setTimeout(addressCheck, 400);
        return;
    }
    //Get the first one on the list.
    var data = addresses[0];
    //Process it.
    geocoder.geocode({address: data}, function() {
        placeMarker();
            //remove the first element from the adresses list.
        addresses.shift();
            //Call the entire function again, so it starts with a new address.
        addressCheck();
    });
}
var placeMarker = function(){
    //Add Marker to GoogleMaps
};

addressCheck();