我试图使自己更加熟悉JPA,因此我创建了一个非常简单的项目。我有一个用户类和一个地址类。即使我将Address添加到User类,我似乎也必须同时坚持这两个要求?
用户:
import javax.persistence.*;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
@Entity
@Table(name = "usr") // @Table is optional, but "user" is a keyword in many SQL variants
@NamedQuery(name = "User.findByName", query = "select u from User u where u.name = :name")
public class User {
@Id // @Id indicates that this it a unique primary key
@GeneratedValue // @GeneratedValue indicates that value is automatically generated by the server
private Long id;
@Column(length = 32, unique = true)
// the optional @Column allows us makes sure that the name is limited to a suitable size and is unique
private String name;
// note that no setter for ID is provided, Hibernate will generate the ID for us
@OneToMany(fetch=FetchType.LAZY, mappedBy="user")
private List<Address> addresses;
地址:
@Entity
public class Address {
@Id // @Id indicates that this it a unique primary key
@GeneratedValue // @GeneratedValue indicates that value is automatically generated by the server
private Long id;
@Column(length=50)
private String address1;
@ManyToOne
@JoinColumn(name="user_id")
private User user;
实体管理器:
EntityManager entityManager = Persistence.createEntityManagerFactory("tutorialPU").createEntityManager();
entityManager.getTransaction().begin();
User user = new User();
user.setName("User");
List<Address> addresses = new ArrayList<Address>();
Address address = new Address();
address.setAddress1("Address1");
addresses.add(address);
user.setAddresses(addresses);
entityManager.persist(user);
entityManager.persist(address);
entityManager.getTransaction().commit();
entityManager.close();
可能做错了什么...只是不知道这是什么吗?
任何建议,将不胜感激。
谢谢,
小号
最佳答案
尝试使用cascade
元素进行注释。
@OneToMany(fetch=FetchType.LAZY, mappedBy="user", cascade=CascadeType.PERSIST)
private List<Address> addresses;
documentation表示默认情况下没有操作级联。它还指出级联操作是可选的,因此它实际上取决于您使用的实现。
另外,在设置关系时,请确保设置关系的双方。将地址设置为用户,并将用户设置为地址。