我需要创建一个POST,可以在同一请求中上传多个文件,但是我不知道如何用grape编写它。现在只上传一个文件,这就是我正在做的,并且工作正常:
desc 'Creates a new attachment.'
params do
requires :file, :type => Rack::Multipart::UploadedFile, :desc => "Attachment File."
end
post do
attachment = Attachment.new
attachment.file = ActionDispatch::Http::UploadedFile.new(params[:file])
attachment.save!
attachment
end
昂首阔步地向我展示了这个:
我正在考虑做这样的事情:
desc 'Creates a new attachment.'
params do
requires :file, :type => Array[Rack::Multipart::UploadedFile], :desc => "Attachment File."
end
但这看起来并不好:
我也尝试过:
params do
optional :attachments, type: Array do
requires :file, :type => Rack::Multipart::UploadedFile, :desc => "Attachment File."
end
end
也不是一个好结果。
什么是正确的处理方式?
最佳答案
经过一些测试,我找到了答案,我将其留在这里:
params do
requires :first_name, type: String, desc: "User first name"
requires :last_name, type: String, allow_blank: false, desc: "User last name"
optional :attachments, type: Array do
requires :file, :type => Rack::Multipart::UploadedFile, :desc => "Profile pictures."
end
end
您不能使用swagger(或至少我没有找到一种方法)来测试它,但是可以使用以下curl:
curl -v -F "first_name=John" -F "last_name=McTest" -F "attachments[][file]=@first_picture.png" -F "attachments[][file]=@second_picture.jpg" http://url/api/users