java - JAXB与 namespace show一起编码？

说我的有效xml如下所示：

<A xmlns="something">
   <B>4</B>
</A>

我的代码是这样的：

@XmlRootElement(name = "A")
@XmlAccessorType (XmlAccessType.FIELD)
@Getter //from lombok
public class Data{

@XmlElement(name = "B")
private String b;

public Data(String b) {
    this.b = b;
}

public Data() {
}
// Getter/setter generated by lombok.
}

我该如何工作？如果我的xml标记具有上面的“ xmlns”之类的一些关联元素，则JAXB解组器将引发异常。

我是第一次这样做，所以我真的对JAXB，拆封等一无所知。我在挣扎。 :)
任何帮助都会很好。

编辑
堆栈跟踪：

javax.xml.bind.UnmarshalException: unexpected element (uri:"something", local:"A"). Expected elements are <{}B>,<{}A>
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:726)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:247)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:242)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportUnexpectedChildElement(Loader.java:109)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext$DefaultRootLoader.childElement(UnmarshallingContext.java:1131)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext._startElement(UnmarshallingContext.java:556)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:538)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.SAXConnector.startElement(SAXConnector.java:153)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.startElement(AbstractSAXParser.java:509)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:374)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl$NSContentDriver.scanRootElementHook(XMLNSDocumentScannerImpl.java:613)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:3132)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(XMLDocumentScannerImpl.java:852)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:602)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:112)
at   com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:505)
at ...

最佳答案

如果您在xml文档中有一个名称空间，则还需要在jaxb批注中包含该名称空间。

例如。像这样：

@XmlRootElement(name = "A", namespace="something")
@XmlAccessorType (XmlAccessType.FIELD)
public class Data{

关于java - JAXB与 namespace show一起编码？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/42874676/

Jaxb

java - JAXB与 namespace show一起编码？