我在RSpec的共享示例中使用定义的变量时遇到麻烦。这是我的测试:

RSpec.shared_examples "check user logged in" do |method, action, params|
  it "redirects to the sign in page if the user is not logged in" do
    send(method, action, params)
    expect(response).to redirect_to(signin_url)
  end
end

RSpec.describe UsersController, type: :controller do
  describe "GET #show" do
    let(:user) { FactoryGirl.create(:user) }
    let!(:show_params) do
      return { id: user.id }
    end

    context "navigation" do
      include_examples "check user logged in", :get, :show, show_params
    end
  end
end


在测试中,我正在检查以确保用户需要先登录才能执行操作。我收到以下错误消息:


  method_missing':show_params在示例组中不可用


我需要更改哪些内容以使show_params可以访问?我试过使用it_behaves_like代替include_examples,但没有运气。我也尝试删除context "navigation"块无济于事。我需要在多个控制器和动作之间执行此检查,因此似乎一个共享的示例可能是重用代码的正确方法。

最佳答案

这里的问题是在示例之外调用了记忆的let帮助器show_params

除了传递参数外,您还可以直接从包含示例的外部范围引用let

RSpec.describe UsersController, type: :controller do
  let(:user) { FactoryGirl.create(:user) }
  describe "GET #show" do
    let(:action) { get :show, id: user }
    it_should_behave_like "an authorized action"
  end
end

RSpec.shared_examples "an authorized action" do
  it "denies access" do
    action
    expect(response).to redirect_to(signin_url)
  end
end


last let always wins开始,这是一个非常强大的模式,可让您使用约定优于配置的方法。

RSpec.describe UsersController, type: :controller do
  let(:user) { FactoryGirl.create(:user) }
  describe "GET #show" do
    let(:action) { get :show, id: user }
    it_should_behave_like "an authorized action"

    context "when signed in" do
      before { sign_in user }
      let(:action) { get :show, id: other_user }
      context 'when viewing another user' do
        it_should_behave_like "an authorized action"
      end
    end
  end
end

07-24 17:54
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