java - 使用Java的XSLT

我在stackoverflow帖子之一中遇到了以下示例-

import javax.xml.transform.*;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import java.io.File;
import java.io.IOException;
import java.net.URISyntaxException;

public class TestMain {
    public static void main(String[] args) throws IOException, URISyntaxException, TransformerException {
        TransformerFactory factory = TransformerFactory.newInstance();
        Source xslt = new StreamSource(new File("transform.xslt"));
        Transformer transformer = factory.newTransformer(xslt);

        Source text = new StreamSource(new File("input.xml"));
        transformer.transform(text, new StreamResult(new File("output.xml")));
    }
}

在上面的示例中，我想将输入用作字符串，将输出用作字符串，并且仅从文件中读取xslt。有可能实现这一目标吗？

最佳答案

用StreamSource https://docs.oracle.com/javase/7/docs/api/javax/xml/transform/stream/StreamSource.html#StreamSource(java.io.InputStream)看一下InputStream构造函数

您可以像这样从string创建输入：

    InputStream input = new ByteArrayInputStream("<your string input>".getBytes(StandardCharsets.UTF_8));
    Source text = new StreamSource(input);

并使用string和StringWriter将输出作为StreamResult：

    StringWriter outputWriter = new StringWriter();
    StreamResult result = new StreamResult( outputWriter );

    transformer.transform( text, result );

    String outputAsString = outputWriter.getBuffer().toString();

关于java - 使用Java的XSLT，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/42800632/