我试图编写这个小脚本来批量重命名文件扩展名。我传递了三个参数,即文件所在的目录,当前扩展名和新扩展名。
我得到的错误是
python batch_file_rename_2.py c:\craig .txt .html
Traceback (most recent call last):
File "batch_file_rename_2.py", line 13, in <module>
os.rename(filename, newfile)
WindowsError: [Error 2] The system cannot find the file specified
该代码是
import os
import sys
work_dir=sys.argv[1]
old_ext=sys.argv[2]
new_ext=sys.argv[3]
files = os.listdir(work_dir)
for filename in files:
file_ext = os.path.splitext(filename)[1]
if old_ext == file_ext:
newfile = filename.replace(old_ext, new_ext)
os.rename(filename, newfile)
最佳答案
os.listdir
仅返回文件名,而不返回完整路径。使用os.path.join
重新创建正确的路径:
for filename in files:
file_ext = os.path.splitext(filename)[1]
if old_ext == file_ext:
newfile = filename.replace(old_ext, new_ext)
os.rename(
os.path.join(work_dir, filename),
os.path.join(work_dir, newfile))
关于python - 争论有问题,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/11825923/