我有一个小问题;在PHP中,我使用curl从URL获取数据:
$url = "http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg";
为此,我使用了
curl_getinfo()
,它给了我一个数组:Array
(
[url] => http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg
[content_type] => image/jpeg
[http_code] => 200
[header_size] => 496
[request_size] => 300
[filetime] => -1
[ssl_verify_result] => 0
[redirect_count] => 0
[total_time] => 2.735
[namelookup_time] => 0.063
[connect_time] => 0.063
[pretransfer_time] => 0.063
[size_upload] => 0
[size_download] => 34739
[speed_download] => 12701
[speed_upload] => 0
[download_content_length] => 34739
[upload_content_length] => -1
[starttransfer_time] => 1.282
[redirect_time] => 0
)
如何在链接
[url] => http://www.prelovac.com/vladimir/wp-content/uploads/2008/03/example.jpg
中获取图像的名称,例如[image_name] : example
[image_ex] : jpg
感谢您的任何建议!
最佳答案
使用pathinfo