我试图用ruby对一个类的两个实例进行单元测试:
def test_example
a = Object.new
b = Object.new
assert_equal a, b
end
我知道这是失败的,因为实例是不同的变量,每个都有自己的内存指针。我要做的是让这个测试通过,如果实例在所有方面都相同,除了它们的引用指针。
下面是一个更为复杂(如果是人为的)的例子:
# Let's stir up something...
class FooBar
attr_accessor :seed, :foo, :bar
def foo_the_bar()
@bar = @seed + @foo * 3
end
end
f = FooBar.new
f.seed = "Mountains "
f.foo = "are just mountains "
f.bar = "obliterate me!"
f.foo_the_bar
p f.bar # "Mountains are just mountains are just mountains are just mountains "
# So far so good, now let's test if one FooBar is same as another...
require 'test/unit'
class FooBarTest < Test::Unit::TestCase
# Test fails: <#<FooBar:0x9a40d18>> expected but was <#<FooBar:0x9a40d04>>.
# But what we really want is a way to make this pass
# since the objects are exactly the same in every respect,
# besides their pointers.
def test_foobar_1_init
f1 = FooBar.new
f2 = FooBar.new
assert_equal f1, f2
end
# Again, test fails, but we want it to pass,
# since the instance variables are the same.
def test_foobar_2_instance_var
f1 = FooBar.new
f2 = FooBar.new
f1.seed = "Santa says "
f1.foo = "ho "
f1.bar = "something"
f1.foo_the_bar
f2.seed = f1.seed
f2.foo = f1.foo
f2.foo_the_bar
assert_equal f1, f2
end
# This test fails for the wrong reason.
# We want this to fail because the instance variables are different.
# This test should also fail if we add a method to one of the instances,
# or make the instances differ from each some other way.
def test_foobar_3_diff
f1 = FooBar.new
f2 = FooBar.new
f1.seed = "Kitty goes "
f1.foo = "meow "
f1.foo_the_bar
f2.seed = "Doggies goes "
f2.foo = "woof "
f2.foo_the_bar
assert_equal f1, f2
end
end
最佳答案
f1.attributes.keys.collect(&:to_sym).each do |field|
assert_equal f1.send(field), f2.send(field)
end
这将断言所有字段的相等性。但缺点是断言的数量。如果不希望发生这种情况,请将ID分配给这样的对象
f1.id = 1
f2.id = 1
assert_equal f1, f2
但请确保不要保存可能导致不一致的对象。
关于ruby - 如何在Ruby中对类实例的相同性/相等性进行单元测试?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13152158/