遇到这个问题,我想通过凹凸发送图像,但是凹凸API的最大块为256kb
if([[NSKeyedArchiver archivedDataWithRootObject:self.selectedImg]length] > 262144)
{
int dlen = [[NSKeyedArchiver
archivedDataWithRootObject:self.selectedImg] length];
NSLog(@"Sending data: %i bytes in %d chunks",dlen,
(int)ceil(((float)dlen / 262144.0f)));
for (int i=1; i <= (int)ceil(((float)dlen / 262144.0f)); i++) {
int maxr=0;
if ((262144*i) > dlen) {
maxr = dlen-(262144*(i-1));
} else {
maxr = 262144;
}
NSData *moveChunk = [[NSKeyedArchiver
archivedDataWithRootObject:self.selectedImg]
subdataWithRange:NSMakeRange(262144*(i-1),maxr)];
NSLog(@"Sending Chunk: %d, %d bytes",i,[moveChunk length]);
[bumpObject sendData:moveChunk];
}
}
else
{
//Data is 254kb or under
NSData *moveChunk = [NSKeyedArchiver
archivedDataWithRootObject:self.selectedImg];
[bumpObject sendData:moveChunk];
}
我如何将所有块一起编译?
花费了3个小时,但无法解决。
最佳答案
好的,我实际上还没有尝试过,但是可以了。
在接收端,将接收到的NSData对象合并到带有-[NSMutableData appendData:]
或-[NSMutableData appendBytes:length:]
的NSMutableData实例中。 (从-[NSData bytes]
和-[NSData length]
中获取字节
然后,使用+[NSKeyedUnarchiver unarchiveObjectWithData:]
取回图像。
...像这样(已经设置了NSMutableData属性,假设称为receivedImageData
)...
- (void) bumpDataReceived:(NSData *)chunk {
if (!self.receivedImageData) {
self.receivedImageData = [NSMutableData dataWithCapacity:[chunk length]];
[self.receivedImageData setData:chunk];
} else {
[self.receivedImageData appendData:chunk];
}
}
...,然后,当您获得最后一个块(
-bumpSessionEnded:
中的大小不等于262144吗?)时,将图像对象返回UIImage* receivedImage = [NSKeyedUnarchiver unarchiveObjectWithData:self.receivedImageData];
做完了!
关于iphone - NSKeyedUnarchiver如何从凹凸中提取多个块?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/10161128/