c++ - 未定义对“操作”的引用

当我用代码块编译该程序时，会得到未定义的对“操作”的引用。我只包含了显示错误的程序的一部分。如何解决此错误？

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
main()
{
     ---------------------
     ---------------------
     while(1)
     {
          printf("Choose from one of the following options :\n");
          printf("1. XXX\n 2. YYY\n 3. ZZZ\n");
          scanf("%d", &choice);
          switch(choice)
         {
             case 1:
             case 2:
             case 3:
             case 4:operations();
             return 0;
             break;
            default: printf("Wrong option choose again\n");
            return 1;
       }

    }
    void operations()
    {
         while(1)
         {
            printf("Choose from one of the following options :\n");
            printf("1. XXX\n2. YYY\n3. ZZZ\n");
                scanf("%d",&choice_of_options);
        switch(choice_of_options)
            {
                ---------
                    ---------
            }
        }
     }
}

最佳答案

您不应该在operations函数中实现main：

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

 void operations()
    {
         while(1)
         {
            printf("Choose from one of the following options :\n");
            printf("1. XXX\n2. YYY\n3. ZZZ\n");
                scanf("%d",&choice_of_options);
        switch(choice_of_options)
            {
                ---------
                    ---------
            }
        }
     }

int main()
{
     ---------------------
     ---------------------
     while(1)
     {
          printf("Choose from one of the following options :\n");
          printf("1. XXX\n 2. YYY\n 3. ZZZ\n");
          scanf("%d", &choice);
          switch(choice)
         {
             case 1:
             case 2:
             case 3:
             case 4:operations();
             return 0;
             break;
            default: printf("Wrong option choose again\n");
            return 1;
       }

    }
}

关于c++ - 未定义对“操作”的引用，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/34483000/