我创建了一个弹出窗口来查看我的设置,
if ([popoverController isPopoverVisible]) {
[popoverController
dismissPopoverAnimated:YES];
} else {
UIView* popoverView = [[UIView alloc]
initWithFrame:CGRectMake(566, 440, 0, 0)];
popoverView.backgroundColor = [UIColor blackColor];
controller1.contentSizeForViewInPopover = CGSizeMake(300, 115);
popoverController = [[UIPopoverController alloc]
initWithContentViewController:controller1];
[popoverController presentPopoverFromRect:popoverView.frame
inView:self.view
permittedArrowDirections:UIPopoverArrowDirectionUp
animated:YES];
}
我的推送操作代码:
UIStoryboard *storyboard = [UIStoryboard
storyboardWithName:@"MainStoryboard"
bundle:nil];
UIViewController *controller = (UIViewController *)[storyboard
instantiateViewControllerWithIdentifier:@"PCBViewController"];
[self.navigationController
pushViewController:controller
animated:YES];
在我的设置中,弹出框有一些按钮。单击那些按钮,通过推操作打开视图控制器,但是它不起作用。
我的问题是:如何设置弹出式内容的推送动作。
最佳答案
您的视图是从popover呈现的,因此self.navigationController将为nil。
尝试这个
UIStoryboard *storyboard = [UIStoryboard
storyboardWithName:@"MainStoryboard"
bundle:nil];
UIViewController *controller = (UIViewController *)[storyboard
instantiateViewControllerWithIdentifier:@"PCBViewController"];
UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:controller];
[navigationController
pushViewController:controller
animated:YES];