java - 读取发送到Dropwizard服务的请求的正文

我需要阅读发送到dropwizard服务的json请求的内容。消息本身由dropwizard序列化为带注释的对象，该对象是方法的输入(PaymentMessage对象)。我已将HttpServletRequest添加为该方法的输入参数。 HttpServletRequest不为null，但方法HttpServletRequest#getInputStream()返回非空但为空的流。

curl 度:curl -i -X POST -H'Content-Type: application/json; charset=UTF-8' \http://localhost:8080/NL/users/555855/payments -d '{"eventId":"110099110099","hznHouseholdId":"1234567_nl","ipAddress":"123.123.123.123","transactionId":"799ef666-e09c-8350-247b-c466997714ad","transactionDate":"2014-09-29T16:56:21Z","appName":"Flappy Bird"}'
编码:

@POST
@Path("/{countryCode}/users/{customerId}/payments")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.APPLICATION_JSON)
public Response processPaymentAction(
        @Context final HttpServletRequest request,
        @Nonnull @PathParam("countryCode") final String countryCode,
        @Nonnull @PathParam("customerId") final String customerId,
        @Valid PaymentMessage paymentMessage)
        throws IOException, ServletException {

    LOG.debug("Request "+request.toString());
    final ByteSource byteSource = new ByteSource() {
        @Override
        public InputStream openStream() throws IOException {
            return request.getInputStream();
        }
    };
    LOG.debug("charset "+request.getCharacterEncoding());
    final String contents = byteSource.asCharSource(Charset.forName(request.getCharacterEncoding())).read();
    LOG.debug("contents: "+contents);
    return Response.status(Response.Status.ACCEPTED).build();
}

最佳答案

您可以将PaymentMessage paymentMessage参数更改为String paymentMessage，该参数应为json字符串。这样就不会进行任何验证，也不会直接拥有POJO。

关于java - 读取发送到Dropwizard服务的请求的正文，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/26317224/