如何在const char*数组中拆分多行字符串。?
这是输入字符串。

const char* str = "122.123,-38.789"
                  "122.123,-39.78";

我需要从这件事中得到两条线。
str1 = "122.123,-38.789";

str2 = "122.123,-39.78";

输出
printf("string='%s'", str)

string='122.123,-38.789122.123,-39.78'

应该做些什么来拆分这个字符串?

最佳答案

使用char数组*

#include <stdio.h>
const char* str[] = { "122.123,-38.789" ,  "122.123,-39.78" };

int main(){
  printf("%s\n%s\n",str[0],str[1] );
  return 0;
}

编译器如何理解您的代码:
C预处理器将字符串连接在一起,
const char* str = "122.123,-38.789"
                  "122.123,-39.78";

字符串之间的换行符被解析为空白,与空格或制表符相同。所以它相当于:
const char* str = "122.123,-38.789" "122.123,-39.78";

预处理器转换为
const char* str = "122.123,-38.789122.123,-39.78";

10-05 20:54
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