python - 在Python3中腌制一个GdkPixbuf.Pixbuf对象

我想在Python3中腌制和腌制GdkPixbuf.Pixbuf。更具体地说，Python3的multiprocessing包需要这样做，因为我通过Queue在进程之间共享此类对象。

问题是对象从

<GdkPixbuf.Pixbuf object at 0x7f8b9e9cfb88 (GdkPixbuf at 0x563b61725c60)>

至

<GdkPixbuf.Pixbuf object at 0x7f8b9e9eaea0 (uninitialized at 0x(nil))>

那是最小的工作示例。

>>> import gi
>>> from gi.repository import GdkPixbuf
__main__:1: PyGIWarning: GdkPixbuf was imported without specifying a version first. Use gi.require_version('GdkPixbuf', '2.0') before import to ensure that the right version gets loaded.

>>> pf = GdkPixbuf.Pixbuf.new_from_file('_icon.png')
>>> pf
<GdkPixbuf.Pixbuf object at 0x7f8b9e9cfb88 (GdkPixbuf at 0x563b61725c60)>

>>> import pickle
>>> pickle.dump(pf, open('p', 'wb'))

>>> pb2 = pickle.load(open('p', 'rb'))
>>> pb2
<GdkPixbuf.Pixbuf object at 0x7f8b9e9eaea0 (uninitialized at 0x(nil))>

我看不到其他泡菜方法。图标需要在单独的进程中加载​​（与应用程序主/第一个进程位于不同的CPU内核上），然后应转移到主进程中。这是通过Queue腌制所有数据来完成的。

最佳答案

我的解决方案不是将“ icon”作为内存中的Pixbuf对象，而是作为我从文件中读取的原始字节。

解开字节后，我将其转换为Pixbuf。

>>> import gi
>>> from gi.repository import GdkPixbuf, Gio, GLib
__main__:1: PyGIWarning: GdkPixbuf was imported without specifying a version first. Use gi.require_version('GdkPixbuf', '2.0') before import to ensure that the right version gets loaded.
>>> with open('_icon.png', 'rb') as f:
...     icon_bytes = f.read()
...
>>>
>>> import pickle
>>> pickle.dump(icon_bytes, open('p', 'wb'))
>>>
>>> pb = pickle.load(open('p', 'rb'))
>>> pb = GLib.Bytes(pb)
>>> pb = GdkPixbuf.Pixbuf.new_from_stream(Gio.MemoryInputStream.new_from_bytes(pb))
>>> pb
<GdkPixbuf.Pixbuf object at 0x7fc0858ac5e8 (GdkPixbuf at 0x55e0d8d08b60)>

关于python - 在Python3中腌制一个GdkPixbuf.Pixbuf对象，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/56207530/