我有以下无序多图：
std::tr1::unordered_multimap<unsigned int, unsigned int > duplicates;
我尝试使用获取键的值
std::pair<std::tr1::unordered_multimap<unsigned int, unsigned int>,std::tr1::unordered_multimap<unsigned int, unsigned int> > range = duplicates.equal_range(id);
然后使用for循环获取多个结果：
for (std::tr1::unordered_multimap<unsigned int, unsigned int>::iterator it=range.first; it!=range.second; ++it)
但我收到以下错误：
ref_impl/core.cpp:306:84: error: conversion from 'std::tr1::unordered_multimap<unsigned int, unsigned int>' to non-scalar type 'std::tr1::_Hashtable<unsigned int, std::pair<const unsigned int, unsigned int>, std::allocator<std::pair<const unsigned int, unsigned int> >, std::_Select1st<std::pair<const unsigned int, unsigned int> >, std::equal_to<unsigned int>, std::tr1::hash<unsigned int>, std::tr1::__detail::_Mod_range_hashing, std::tr1::__detail::_Default_ranged_hash, std::tr1::__detail::_Prime_rehash_policy, false, false, false>::iterator {aka std::tr1::__detail::_Hashtable_iterator<std::pair<const unsigned int, unsigned int>, false, false>}' requested
ref_impl/core.cpp:306:101: error: no match for 'operator!=' in 'it != range.std::pair<std::tr1::unordered_multimap<unsigned int, unsigned int>, std::tr1::unordered_multimap<unsigned int, unsigned int> >::second'
有什么建议么？
最佳答案
unordered_multimap::equal_range返回一对迭代器，而不是一对unordered_multimap。将第二行更改为以下内容，一切正常：
typedef std::tr1::unordered_multimap<unsigned int, unsigned int>::iterator iterator;
std::pair<iterator, iterator> range = duplicates.equal_range(id);
关于c++ - 遍历equal_range结果集，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/15444840/