我以这种方式定义状态:

var parentStates = [
 {state : 'home', url: '/home', template: 'home.html'},
 {state : 'about', url: '/about', template: 'about.html'},
 {state : 'contact', url: '/contact', template: 'contact.html'},
 {state : 'home.data', url: '', template: 'data.html'},
 {state : 'about.data', url: '', template: 'data.html'},
 {state : 'contact.data', url: '', template: 'data.html'}
];

$urlRouterProvider.otherwise("/main/home");

$stateProvider
 .state("main", { abtract: true, url:"/main",
    views: {
        "viewA": {
            templateUrl:"main.html"
        }
    }
});
parentStates.forEach(function(value){
    $stateProvider
    .state("main." + value.state, {
        url: value.url,
        views: {
            "": {
                templateUrl: value.template
            }
        },
    })
});

我想写一个'decorator',用于根据'templateUrl' (如上所示, View 的名称为空)来设置 View 的名称。

这是装饰器的代码:
$stateProvider.decorator('views', function (state, parent) {
 var result = {},
 views = parent(state);

 // Don't touch the 'main state'
 if (state.name === "main") {
  return views;
 }

 angular.forEach(views, function (config, name) {
    if(config.templateUrl=='data.html'){
        result[name] = 'viewC@main';
    }
    else{
        result[name] = 'viewB@main';
    }
 });
return result;
});

当然,这是行不通的。我有点迷路了。

最佳答案

a working plunker

你快到了。让我们简化一下状态定义(因为我们不需要嵌套的view对象,我们将在以后创建它):

parentStates.forEach(function(value) {
    $stateProvider
      .state("main." + value.state, {
        url: value.url,
        templateUrl: value.template,
      })
  });

这将是装饰器:
  $stateProvider.decorator('views', function(state, parent) {
    var result = {},
      views = parent(state);

    // some example when to not inject resolve
    if (state.name === "main") {
      return views;
    }

    angular.forEach(views, function(config, name) {

      // the super child template
      if(config.templateUrl === 'data.html'){
        result['viewC@main'] = config;
      }
      else{
        result['viewB@main'] = config;
      }
    });

    return result;
  });

检查here

还要注意以下几点:
  • How to decorate current state resolve function in UI-Router? Current function isn't invoked
  • AngularJS: How to set one state as a global parent in UI-Router (to use modal as common parts)
  • 关于javascript - 从装饰器设置 View 名称-Angular Ui Router,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33112912/

    10-12 02:59
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