我遇到了不确定如何解决的问题。我相信这是GCC和/或libstdc++中的问题。
我正在使用GCC 4.8.2-19ubuntu1,libstdc++ 3.4.19(我相信?How do you find what version of libstdc++ library is installed on your linux machine?)和Ubuntu 1.55运行Ubuntu 14.04 LTS。
这是代码:
// http://www.boost.org/doc/libs/1_54_0/libs/log/doc/html/log/tutorial.html
// with a slight modification to ensure we're testing with threads too
// g++ -g -O0 --std=c++11 staticlinktest.cpp -lboost_log_setup -lboost_log -lboost_system -lboost_filesystem -lboost_thread -lpthread
#define BOOST_ALL_DYN_LINK 1
#include <boost/log/trivial.hpp>
#include <thread>
#include <atomic>
#include <vector>
int main(int, char*[])
{
BOOST_LOG_TRIVIAL(trace) << "A trace severity message";
BOOST_LOG_TRIVIAL(debug) << "A debug severity message";
BOOST_LOG_TRIVIAL(info) << "An informational severity message";
BOOST_LOG_TRIVIAL(warning) << "A warning severity message";
BOOST_LOG_TRIVIAL(error) << "An error severity message";
BOOST_LOG_TRIVIAL(fatal) << "A fatal severity message";
std::atomic<bool> exiting(false);
std::vector<std::thread> threads;
for ( int i = 0; i < 8; ++i ) {
threads.push_back(std::thread([&exiting](){
while (!exiting)
BOOST_LOG_TRIVIAL(trace) << "thread " << std::this_thread::get_id() << " trace";
}));
}
usleep(1000000);
exiting = true;
std::for_each(threads.begin(), threads.end(), [](std::thread& t){
t.join();
});
return 0;
}
问题:
使用顶部的命令行,我将使用动态链接进行构建。一切似乎都很好。我看到带有线程ID和跟踪信息的看似有效的输出。
但是,在我的项目中,我需要能够使用静态链接。因此,我将“-static”开关添加到g++命令中,并注释掉BOOST_ALL_DYN_LINK的#define。它建立得很好。但是,当我执行该程序时,它会一直运行直到创建第一个线程,然后出现段错误。回溯似乎总是相同的:
#0 0x0000000000000000 in ?? ()
#1 0x0000000000402805 in __gthread_equal (__t1=140737354118912, __t2=0) at /usr/include/x86_64-linux-gnu/c++/4.8/bits/gthr-default.h:680
#2 0x0000000000404116 in std::operator== (__x=..., __y=...) at /usr/include/c++/4.8/thread:84
#3 0x0000000000404c03 in std::operator<< <char, std::char_traits<char> > (__out=..., __id=...) at /usr/include/c++/4.8/thread:234
#4 0x000000000040467e in boost::log::v2s_mt_posix::operator<< <char, std::char_traits<char>, std::allocator<char>, std::thread::id> (strm=...,
value=...) at /usr/include/boost/log/utility/formatting_ostream.hpp:710
#5 0x0000000000402939 in __lambda0::operator() (__closure=0x7bb5e0) at staticlinktest.cpp:27
#6 0x0000000000403ea8 in std::_Bind_simple<main(int, char**)::__lambda0()>::_M_invoke<>(std::_Index_tuple<>) (this=0x7bb5e0)
at /usr/include/c++/4.8/functional:1732
#7 0x0000000000403dff in std::_Bind_simple<main(int, char**)::__lambda0()>::operator()(void) (this=0x7bb5e0)
at /usr/include/c++/4.8/functional:1720
#8 0x0000000000403d98 in std::thread::_Impl<std::_Bind_simple<main(int, char**)::__lambda0()> >::_M_run(void) (this=0x7bb5c8)
at /usr/include/c++/4.8/thread:115
#9 0x000000000047ce60 in execute_native_thread_routine ()
#10 0x000000000042a962 in start_thread (arg=0x7ffff7ffb700) at pthread_create.c:312
#11 0x00000000004e5ba9 in clone ()
在我看来,它似乎是在尝试仅在静态链接时才调用空函数指针。有什么想法吗?难道我做错了什么?
最佳答案
将libpthread
静态链接到您的应用程序是really bad idea。
尽管如此,这是如何做到的。
我首先修复了编译错误(我怀疑您没有向我们展示您实际上正在编译的代码,或者boost严重污染了 namespace ),然后删除了不相关的boost内容,这只会给问题增加噪音。这是代码:
#include <atomic>
#include <chrono>
#include <iostream>
#include <thread>
#include <vector>
int main(int, char*[])
{
std::atomic<bool> exiting(false);
std::vector<std::thread> threads;
for ( int i = 0; i < 8; ++i ) {
threads.push_back(std::thread([&exiting](){
while (!exiting)
std::cout << "thread " << std::this_thread::get_id() << " trace\n";
}));
}
std::this_thread::sleep_for(std::chrono::milliseconds(1));
exiting = true;
for(auto& t : threads){
t.join();
};
return 0;
}
如果我动态链接,它运行良好,但静态链接时崩溃:
terminate called after throwing an instance of 'std::system_error'
what(): Operation not permitted
Aborted (core dumped)
根据this e-mail,如果您使用线程和静态链接,则必须正确配置
libstdc++
。这是使它与静态链接一起使用的不可思议的标志:g++ -std=c++11 -pedantic -pthread threads.cpp -static -Wl,--whole-archive -lpthread -Wl,--no-whole-archive
如前所述,将
libpthread
静态链接到您的应用程序会带来麻烦。