嗨,我在做一个练习项目,可以用我放的坐标画一条线。屏幕只需要文本字段和一个按钮。例如,如果我在这两个文本字段中输入“20”和“30”,然后单击“绘制”按钮,我希望应用程序在另一个视图中绘制一条从(0,0)到(20,30)的线。
我已经知道如何使用“ondraw()”来画一条线,但我不知道如何将这两个参数传递到ondraw()函数中。另外,我应该在每次单击“绘图”按钮时创建一个新视图,还是只在一个视图中更改ondraw()函数?
谢谢!!!!!!!!!!

最佳答案

所以你要做的是避免观点之间互相担心。您有一个处理绘制线的视图,两个处理输入的EditText视图,以及一个提交坐标的按钮。假设您有一个包含这些视图的布局,下面是一个简单的自定义视图示例,您可以使用它来绘制线:

public class LineView extends View {
    /**
     * Container to hold the x1, y1, x2, y2 values, respectively
     */
    private float[] mCoordinates;

    /**
     * The paint with which the line will be drawn
     */
    private Paint mLinePaint = new Paint(Paint.ANTI_ALIAS_FLAG);

    public LineView (Context context) {
        super(context);
    }

    public LineView (Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    public LineView (Context context, AttributeSet attrs, int defStyle) {
        super(context, attrs, defStyle);
    }

    /**
     * Set the color with which the line should be drawn
     * @param color the color to draw the line with
     */
    public void setLineColor (int color) {
        mLinePaint.setColor(color);
        invalidate();
    }

    /**
     * Set the coordinates of the line to be drawn. The origin (0, 0) is the
     * top left of the View.
     * @param x1 the starting x coordinate
     * @param y1 the starting y coordinate
     * @param x2 the ending x coordinate
     * @param y2 the ending y coordinate
     */
    public void setCoordinates (float x1, float y1, float x2, float y2) {
        ensureCoordinates();

        mCoordinates[0] = x1;
        mCoordinates[1] = y1;
        mCoordinates[2] = x2;
        mCoordinates[3] = y2;

        invalidate();
    }

    private void ensureCoordinates () {
        if (mCoordinates == null) {
            mCoordinates = new float[4];
        }
    }

    @Override
    protected void onDraw (Canvas canvas) {
        if (mCoordinates != null) {
            canvas.drawLine(
                    mCoordinates[0],
                    mCoordinates[1],
                    mCoordinates[2],
                    mCoordinates[3],
                    mLinePaint
            );
        }
    }
}

结合一个简单的例子,考虑到上面对你的布局所做的假设,你可以如何实现它。
public class EditTextActivity extends Activity implements View.OnClickListener {
    private EditText mInputX;
    private EditText mInputY;
    private Button mDrawButton;
    private LineView mLineView;

    public void onCreate (Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.my_layout);

        mInputX = (EditText) findViewById(R.id.input_x);
        mInputY = (EditText) findViewById(R.id.input_y);
        mDrawButton = (Button) findViewById(R.id.draw_button);

        mLineView = (LineView) findViewById(R.id.line_view);
        mLineView.setColor(Color.GREEN);

        mDrawButton.setOnClickListener(this);
    }

    @Override
    public void onClick (View v) {
        final float x1 = 0;
        final float y1 = 0;
        final float x2 = getValue(mInputX);
        final float y2 = getValue(mInputY);

        mLineView.setCoordinates(x1, y1, x2, y2);
    }

    private static float getValue (EditText text) {
        try {
            return Float.parseFloat(text.getText().toString());
        } catch (NumberFormatException ex) {
            return 0;
        }
    }
}

关于android - Android-如何绘制具有特定参数的多变线?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/18809217/

10-14 12:09
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