我有一个嵌套的字典:
Night_interval={
'2010': {
Timestamp('2010-07-01 00:00:00'): 29,
Timestamp('2010-07-02 00:00:00'): 28,
Timestamp('2010-07-03 00:00:00'): 28,
Timestamp('2010-07-04 00:00:00'): 29,
Timestamp('2010-07-05 00:00:00'): 28
},
'2011': {
Timestamp('2010-07-01 00:00:00'): 29,
Timestamp('2010-07-02 00:00:00'): 28,
Timestamp('2010-07-03 00:00:00'): 28,
Timestamp('2010-07-04 00:00:00'): 29,
Timestamp('2010-07-05 00:00:00'): 28
},
'2012': {
Timestamp('2010-07-01 00:00:00'): 29,
Timestamp('2010-07-02 00:00:00'): 28,
Timestamp('2010-07-03 00:00:00'): 28,
Timestamp('2010-07-04 00:00:00'): 29,
Timestamp('2010-07-05 00:00:00'): 28
}
}
使用此字典,我想创建一个与每个键(即
2010
,2011
和2012
)关联的数据帧的字典。我还想将时间戳记作为每个数据框中的索引。我尝试编写以下代码:Years = ['2010','2011','2012']
for key in Years:
df_interval[key] = pd.DataFrame(Night_interval[key])
但是,我收到此错误:
ValueError: If using all scalar values, you must pass an index
我找不到我做错了的地方。我将不胜感激任何帮助。
最佳答案
如果需要dict,请使用DataFrame
构造函数和列名:
df_interval = {}
Years = ['2010','2011','2012']
for key in Years:
df_interval[key] = pd.DataFrame({key:Night_interval[key]})
print (df_interval['2012'])
2012
2010-07-01 29
2010-07-02 28
2010-07-03 28
2010-07-04 29
2010-07-05 28
df_interval = {}
Years = ['2010','2011','2012']
for key in Years:
df_interval[key] = pd.DataFrame({'a':Night_interval[key]})
print (df_interval['2012'])
a
2010-07-01 29
2010-07-02 28
2010-07-03 28
2010-07-04 29
2010-07-05 28
或者,如果可能只有一列,请创建
dict
的Series
:df_interval = {}
Years = ['2010','2011','2012']
for key in Years:
df_interval[key] = pd.Series(Night_interval[key], name=key)
print (df_interval['2012'])
2010-07-01 29
2010-07-02 28
2010-07-03 28
2010-07-04 29
2010-07-05 28
Name: 2012, dtype: int64