python - 在一行上格式化某些JSON对象

考虑以下代码:

>>> import json
>>> data = {
...     'x': [1, {'$special': 'a'}, 2],
...     'y': {'$special': 'b'},
...     'z': {'p': True, 'q': False}
... }
>>> print(json.dumps(data, indent=2))
{
  "y": {
    "$special": "b"
  },
  "z": {
    "q": false,
    "p": true
  },
  "x": [
    1,
    {
      "$special": "a"
    },
    2
  ]
}

我想要的是格式化JSON，以便仅具有单个属性'$special'的JSON对象在一行上呈现，如下所示。

{
  "y": {"$special": "b"},
  "z": {
    "q": false,
    "p": true
  },
  "x": [
    1,
    {"$special": "a"},
    2
  ]
}

我玩过实现自定义 JSONEncoder 并将其作为json.dumps参数传递给cls的方法，但是JSONEncoder上的两个方法都有一个问题:

为JSONEncoder的每个部分调用default data 方法，但是返回值不是原始的JSON字符串，因此似乎没有任何方法可以调整其格式。

JSONEncoder encode 方法的确返回原始JSON字符串，但整个data仅被调用一次。

有什么办法可以让JSONEncoder做我想做的事情？

最佳答案

json模块并不是真正为您提供对输出的太多控制；缩进主要是为了在调试时提高可读性。

您可以使用标准库 json module来转换输出，而不是让tokenize产生输出:

import tokenize
from io import BytesIO


def inline_special(json_data):
    def adjust(t, ld,):
        """Adjust token line number by offset"""
        (sl, sc), (el, ec) = t.start, t.end
        return t._replace(start=(sl + ld, sc), end=(el + ld, ec))

    def transform():
        with BytesIO(json_data.encode('utf8')) as b:
            held = []  # to defer newline tokens
            lastend = None  # to track the end pos of the prev token
            loffset = 0     # line offset to adjust tokens by
            tokens = tokenize.tokenize(b.readline)
            for tok in tokens:
                if tok.type == tokenize.NL:
                    # hold newlines until we know there's no special key coming
                    held.append(adjust(tok, loffset))
                elif (tok.type == tokenize.STRING and
                        tok.string == '"$special"'):
                    # special string, collate tokens until the next rbrace
                    # held newlines are discarded, adjust the line offset
                    loffset -= len(held)
                    held = []
                    text = [tok.string]
                    while tok.exact_type != tokenize.RBRACE:
                        tok = next(tokens)
                        if tok.type != tokenize.NL:
                            text.append(tok.string)
                            if tok.string in ':,':
                                text.append(' ')
                        else:
                            loffset -= 1  # following lines all shift
                    line, col = lastend
                    text = ''.join(text)
                    endcol = col + len(text)
                    yield tokenize.TokenInfo(
                        tokenize.STRING, text, (line, col), (line, endcol),
                        '')
                    # adjust any remaining tokens on this line
                    while tok.type != tokenize.NL:
                        tok = next(tokens)
                        yield tok._replace(
                            start=(line, endcol),
                            end=(line, endcol + len(tok.string)))
                        endcol += len(tok.string)
                else:
                    # uninteresting token, yield any held newlines
                    if held:
                        yield from held
                        held = []
                    # adjust and remember last position
                    tok = adjust(tok, loffset)
                    lastend = tok.end
                    yield tok

    return tokenize.untokenize(transform()).decode('utf8')

这样可以成功重新格式化您的样本:

import json

data = {
    'x': [1, {'$special': 'a'}, 2],
    'y': {'$special': 'b'},
    'z': {'p': True, 'q': False}
}

>>> print(inline_special(json.dumps(data, indent=2)))
{
  "x": [
    1,
    {"$special": "a"},
    2
  ],
  "y": {"$special": "b"},
  "z": {
    "p": true,
    "q": false
  }
}

关于python - 在一行上格式化某些JSON对象，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/40028755/