string - Scala 运行时字符串插值/格式化

是否有任何标准库工具可以在运行时进行字符串插值/格式化？我希望格式的行为与基于宏的 s"scala ${implementation} 完全相同，只是我的字符串格式是在运行时从配置文件加载的。

val format = config.getString("my.key")
val stringContext = parseFormat(format)
val res = stringContext.f("arg1", "arg2")

parseFormat 返回一个 StringContext 。

我想，在最坏的情况下，我可以在“{}”序列上拆分字符串并使用这些部分来构造 StringContext。

// untested
def parseFormat(format: String): StringContext =
  new StringContext("""{}""".r.split(format): _*)

是否有我遗漏的明显解决方案，或者上述 hack 是否可以解决问题？

最佳答案

没有愚蠢的问题。只有星期天早上。

首先， don't use String.format 。

scala> val s = "Count to %d"
s: String = Count to %d

scala> String format (s, 42)
<console>:9: error: overloaded method value format with alternatives:
  (x$1: java.util.Locale,x$2: String,x$3: Object*)String <and>
  (x$1: String,x$2: Object*)String
 cannot be applied to (String, Int)
              String format (s, 42)
                     ^

scala> s format 42
res1: String = Count to 42

但是格式化可能很昂贵。因此，您可以选择逃生处理:

scala> StringContext("Hello, {}. Today is {}." split "\\{}" : _*).s("Bob", "Tuesday")
res2: String = Hello, Bob. Today is Tuesday.

scala> StringContext("""Hello, \"{}.\" Today is {}.""" split "\\{}" : _*).s("Bob", "Tuesday")
res3: String = Hello, "Bob." Today is Tuesday.

scala> StringContext("""Hello, \"{}.\" Today is {}.""" split "\\{}" : _*).raw("Bob", "Tuesday")
res4: String = Hello, \"Bob.\" Today is Tuesday.

事实证明 split 并没有完全破解它。

scala> StringContext("Count to {}" split "\\{}" : _*) s 42
java.lang.IllegalArgumentException: wrong number of arguments (1) for interpolated string with 1 parts
  at scala.StringContext.checkLengths(StringContext.scala:65)
  at scala.StringContext.standardInterpolator(StringContext.scala:121)
  at scala.StringContext.s(StringContext.scala:94)
  ... 33 elided

所以给出

scala> val r = "\\{}".r
r: scala.util.matching.Regex = \{}

scala> def parts(s: String) = r split s
parts: (s: String)Array[String]

也许

scala> def f(parts: Seq[String], args: Any*) = (parts zip args map (p => p._1 + p._2)).mkString
f: (parts: Seq[String], args: Any*)String

所以

scala> val count = parts("Count to {}")
count: Array[String] = Array("Count to ")

scala> f(count, 42)
res7: String = Count to 42

scala> f(parts("Hello, {}. Today is {}."), "Bob", "Tuesday")
res8: String = Hello, Bob. Today is Tuesday

嘿，等等!

scala> def f(parts: Seq[String], args: Any*) = (parts.zipAll(args, "", "") map (p => p._1 + p._2)).mkString
f: (parts: Seq[String], args: Any*)String

scala> f(parts("Hello, {}. Today is {}."), "Bob", "Tuesday")
res9: String = Hello, Bob. Today is Tuesday.

或者

scala> def f(parts: Seq[String], args: Any*) = (for (i <- 0 until (parts.size max args.size)) yield (parts.applyOrElse(i, (_: Int) => "") + args.applyOrElse(i, (_: Int) => ""))).mkString
f: (parts: Seq[String], args: Any*)String

或者

scala> def f(parts: Seq[String], args: Any*) = { val sb = new StringBuilder ; for (i <- 0 until (parts.size max args.size) ; ss <- List(parts, args)) { sb append ss.applyOrElse(i, (_: Int) => "") } ; sb.toString }
f: (parts: Seq[String], args: Any*)String

scala> f(parts("Hello, {}. Today is {}. {}"), "Bob", "Tuesday", "Bye!")
res16: String = Hello, Bob. Today is Tuesday. Bye!

关于string - Scala 运行时字符串插值/格式化，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/22643036/