如果是错误的 SOAP 请求,我需要获取错误的详细信息。
我正在使用JAX-WS创建Web服务客户端。我的问题是,在错误的事务期间,Web服务客户端能够捕获SOAPFaultException,但没有详细信息:
javax.xml.ws.soap.SOAPFaultException: Component Interface API. at com.sun.xml.internal.ws.fault.SOAP11Fault.getProtocolException(SOAP11Fault.java:178)
如果我通过SOAPUI发送请求,则可以得到响应,其中包含以下详细信息:
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"> <SOAP-ENV:Body>
<SOAP-ENV:Fault>
<faultcode>SOAP-ENV:Server</faultcode>
<faultstring>Component Interface API.</faultstring>
<detail>
<IBResponse type="Error">
<DefaultTitle>Integration Broker Response</DefaultTitle>
<StatusCode>20</StatusCode>
<MessageSetID>180</MessageSetID>
<MessageID>117</MessageID>
<DefaultMessage>You are allowed to claim one meal per day</DefaultMessage>
<MessageParameters>
<keyinformation>
<EMPLID>112233</EMPLID>
</keyinformation>
</MessageParameters>
</IBResponse>
</detail>
</SOAP-ENV:Fault> </SOAP-ENV:Body> </SOAP-ENV:Envelope>
我是否错过了Web服务客户端中的任何配置?提前谢谢了。
最佳答案
要从javax.xml.ws.soap.SOAPFaultException
获取详细信息:
try {
//... invoke service via client
} catch (javax.xml.ws.soap.SOAPFaultException soapFaultException) {
javax.xml.soap.SOAPFault fault = soapFaultException.getFault(); //<Fault> node
javax.xml.soap.Detail detail = fault.getDetail(); // <detail> node
Iterator detailEntries = detail.getDetailEntries(); //nodes under <detail>
//application / service-provider-specific XML nodes (type javax.xml.soap.DetailEntry) from here
}
请参阅相关的javadocs,以获取可以从以下构造中获取的方法/信息: