我使用以下代码在AlarmManager中设置重复事件:

mAlarmManager.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(),
    PERIOD, getPendingIntent(time));


接收方代码:

public class NotificationsReceiver extends BroadcastReceiver {
    public static final String NOTIFICATION_INFO="notification_info";

    @Override
    public void onReceive(Context context, Intent intent) {
       playSound(context);
       Intent i=new Intent(context, MainActivity.class);
       i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
       context.startActivity(i);
    }

    private void playSound(Context context) {
        Uri notification=RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
        RingtoneManager.getRingtone(context, notification).play();
    }
}


有一个问题-事件发生时我需要播放音乐,但是如果我的设备处于睡眠状态,我听不到任何信号!但是,当我唤醒设备时,我会听到音乐。我该如何解决?

最佳答案

当我必须这样做时,我创建以下类:

import android.content.Context;
import android.os.PowerManager;

public abstract class WakeLocker {
    private static PowerManager.WakeLock wakeLock;

    public static void acquire(Context context) {
        if (wakeLock != null) wakeLock.release();

        PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
        wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK |
                PowerManager.ACQUIRE_CAUSES_WAKEUP |
                PowerManager.ON_AFTER_RELEASE, "WakeLock");
        wakeLock.acquire();
    }

    public static void release() {
        if (wakeLock != null) wakeLock.release(); wakeLock = null;
    }
}


然后,您可以拨打WakeLocker.acquire(getApplicationContext());唤醒电话,但不要忘记在操作完成后拨打WakeLocker.release();

此外,将以下权限添加到清单中:<uses-permission android:name="android.permission.WAKE_LOCK" />

希望能有所帮助。

07-28 02:01
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