我使用以下代码在AlarmManager
中设置重复事件:
mAlarmManager.setRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(),
PERIOD, getPendingIntent(time));
接收方代码:
public class NotificationsReceiver extends BroadcastReceiver {
public static final String NOTIFICATION_INFO="notification_info";
@Override
public void onReceive(Context context, Intent intent) {
playSound(context);
Intent i=new Intent(context, MainActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
private void playSound(Context context) {
Uri notification=RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
RingtoneManager.getRingtone(context, notification).play();
}
}
有一个问题-事件发生时我需要播放音乐,但是如果我的设备处于睡眠状态,我听不到任何信号!但是,当我唤醒设备时,我会听到音乐。我该如何解决?
最佳答案
当我必须这样做时,我创建以下类:
import android.content.Context;
import android.os.PowerManager;
public abstract class WakeLocker {
private static PowerManager.WakeLock wakeLock;
public static void acquire(Context context) {
if (wakeLock != null) wakeLock.release();
PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK |
PowerManager.ACQUIRE_CAUSES_WAKEUP |
PowerManager.ON_AFTER_RELEASE, "WakeLock");
wakeLock.acquire();
}
public static void release() {
if (wakeLock != null) wakeLock.release(); wakeLock = null;
}
}
然后,您可以拨打
WakeLocker.acquire(getApplicationContext());
唤醒电话,但不要忘记在操作完成后拨打WakeLocker.release();
。此外,将以下权限添加到清单中:
<uses-permission android:name="android.permission.WAKE_LOCK" />
希望能有所帮助。