GameScore
对象具有一个名为Relation
的Badges
字段。
如何在查询中获取此关系中所有对象的计数:
var GameScore = Parse.Object.extend("GameScore");
var query = new Parse.Query(GameScore);
query.equalTo("playerName", "Dan Stemkoski");
query.find({
success: function(results) {
alert("Successfully retrieved " + results.length + " scores.");
// Do something with the returned Parse.Object values
for (var i = 0; i < results.length; i++) {
var object = results[i];
alert(object.id + ' - ' + object.get('playerName'));
}
},
error: function(error) {
alert("Error: " + error.code + " " + error.message);
}
});
我需要类似的东西:
object.Badges.count
要么
object.Badges.length
最佳答案
Parse.Relation
对象实际上是一个查询描述,它将返回该关系中的对象,因此在这种情况下,您需要为每个GameScore
运行另一个查询:
query.find().then(function (gameScores) {
alert("Successfully retrieved " + gameScores.length + " scores.");
var countPromises = gameScores.map(function (gs) {
// the following executes a count() query, which is severely penalized by Parse
return gs.get('Badges').query().count()
.then(function (count) {
// this extra step is to add the retrieved count as an extra property to the GameSccore object,
// instead of returning only the counts
gs.count = count;
return gs;
});
});
return Parse.Promise.when(countPromises);
}).then(function () {
var gameScoresWithBadgeCount = Array.prototype.slice.call(arguments);
}).fail(function(error) {
alert("Error: " + error.code + " " + error.message);
});
这会导致很多额外的往返(由于
alert()
我假设您在浏览器环境中),并调用count()
查询,这些查询还受Parse限制。我可以建议您将计数缓存保留为
GameScore
类的额外字段,并通过CloudCode挂钩相应地对其进行更新。另外,您可以尝试避免使用Relation
并尽可能地使用等价的using an Array field,通过该方法,您始终可以根据需要始终include相关徽章,也可以完全不查询它们而获得它们的数量!